What is the distance of the third charge?

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Homework Help Overview

The discussion revolves around a problem involving three point charges: 3.0 μC, -5.0 μC, and 0 μC. The original poster seeks to determine the distance from the second charge to the third charge, given that the distance between the first and second charges is 40 m. The context involves concepts from electrostatics, particularly Coulomb's law.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants question the clarity of the problem, particularly regarding the nature of the third charge and whether the system is in equilibrium. There are discussions about the implications of the third charge being neutral and the conditions for equilibrium.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some have suggested reconsidering the assumptions about the third charge and its impact on the system's behavior. There is no explicit consensus on how to proceed, but various lines of reasoning are being examined.

Contextual Notes

Participants note the ambiguity regarding the third charge's neutrality and its effect on the equilibrium of the system, which may influence the ability to solve the problem. The original poster expresses uncertainty about how to begin addressing the problem.

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Homework Statement



Three point charges, 3.0 \muc, -5.0\muc and 0 \muc.

If the distance from point 1 (3.0) and point 2 (-5.0) is 40m, what is the distance from point 2 to point 3?

Homework Equations



coulombs law


[b

The Attempt at a Solution



I don't know how to start this :(
 
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The problem is not clear. Whether the third body is neutral?
Are they in equilibrium?
 
I'm not really sure since I only remembered this problem by memory :( but if the third body WAS neutral and they ARE in equilibrium, how would you answer this? :D
 
haengbon said:
I'm not really sure since I only remembered this problem by memory :( but if the third body WAS neutral and they ARE in equilibrium, how would you answer this? :D
If the third body WAS neutral and they cannot be in equilibrium
 
rl.bhat said:
If the third body WAS neutral and they cannot be in equilibrium

um, if that's so, is it then possible to be solved?

I need to use this formula :D ?

Fe = \frac{ Kq1q2 }{ r2 }
 
No. Just think about it. If the third body is neutral, the other two would attract each other, accelerate towards each other, and eventually collide.
 

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