What is the distance to the target?

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Homework Help Overview

The discussion revolves around a physics problem involving projectile motion and sound propagation. A person fires a rifle horizontally at a target, and the time taken for the bullet to strike the target and for the sound to return to the shooter is given as 1.00 seconds. The problem requires determining the distance to the target using the bullet's speed and the speed of sound, which is influenced by air temperature.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss different formulas for calculating the speed of sound and question the original poster's approach. Some suggest using a more general formula for sound speed and others provide their calculations while seeking confirmation of their methods. There are inquiries about the reasoning behind adding the times for the bullet and sound travel.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and reasoning. Some guidance has been offered regarding the interpretation of the problem and the application of formulas, but there is no explicit consensus on the correct approach or solution yet.

Contextual Notes

Participants note the importance of understanding the relationship between the bullet's travel time and the sound's travel time, as well as the impact of air temperature on the speed of sound. There is also a reminder of the forum's guidelines against providing direct solutions to homework problems.

oneplusone
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Hello.

Homework Statement



A person holds a rifle horizontally and fires at a target. The bullet has a muzzle speed of 20 m/s and the person hears the bullet strike the target 1.00s after firing it. The air temperature is 72 degrees F. What is the distance to the target?


Homework Equations



speed of sound = 331 + 0.6*T (where T =temp in celsius)


Note

I tried solving the problem, and got a different answer than from my solutions manuel. I was just wondering how everyone else would solve it.
 
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oneplusone said:
speed of sound = 331 + 0.6*T (where T =temp in celsius)

I think you should use the more general formula for the speed of sound that is sqrt(gamma*RT/M). Moreover, show your attempt with the formula you used.
 
darkxponent said:
I think you should use the more general formula for the speed of sound that is sqrt(gamma*RT/M). Moreover, show your attempt with the formula you used.
... and the answer from the solutions manual.
(Fwiw, I would have thought drag on the bullet would be more significant than variations in the speed of sound.)
 
(°F - 32) * 5/9 = °C
(72 - 32) * 5/9 = 22.22 °C
22.22*0.6 + 331 = 344.33 m/s

it takes one second for the bullet to reach the target and then for the sound to travel back to you so using
d=vt
t(1s) = (d/344.3)+(d/20)
factor out a d

1s = d((1/344.3)+(1/20))
d = 1/((1/344.3)+(1/20))
d = 18.9 m

Hope I did that correctly and hope you could follow along! This should be the answer you get
 
Last edited:
Not sure how to delete a post so i guess this will stay here emarrasingly indefinitely
 
Last edited:
cmcraes said:
Not sure how to delete a post so i guess this will stay here emarrasingly indefinitely
The main problem with your post is that it is not how this forum works. We don't do people's homework for them. The idea is to nudge in the right direction and point out flaws in arithmetic, algebra or reasoning. So far, oneplusone has not posted enough detail to comment on (beyond that comment).
 
ok sorry :/
 
Hello,

Sorry, i wasn't able to get onto a computer until now.
I did what cmcraes did, except I subtracted instead of added.
Is the reason why you added that the bullet pushes the air which creates the sound, so the sound is the combined velocity of the bullet and the sound? or why do you add?
And this isn't a homework question, (I'm trying to learn physics on my own).
 
You add because you have to remember that From the time you pull the trigger, to when the sound reaches your ears is one second. So you add the time it takes the bullet to hit the target to the time it takes the sound to reach you from the target.
(since that equals 1, and t=d/v, than (d/V_sound + d/V_Bullet) must equal one!) hope that made sense! :)
 
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