MHB What is the domain for ax^(1/3) + b?

  • Thread starter Thread starter mathdad
  • Start date Start date
  • Tags Tags
    Domain
AI Thread Summary
The discussion centers on determining the domain of the function ax^(1/3) + b. Initially, it is suggested that the domain is x ≥ 0 due to the presence of a radical. However, it is clarified that the cube root function is defined for all real numbers, meaning the domain encompasses all real numbers. This distinction is made to highlight that unlike square roots, cube roots can accept negative inputs. Ultimately, the correct domain for the function is confirmed to be all real numbers.
mathdad
Messages
1,280
Reaction score
0
Precalculus by David Cohen, 3rd Edition
Chapter 1, Section 1.3.
Question 3b.

Specify the domain.

ax^(1/3) + b

Solution:

x^(1/3) means the cube root of x.

Since there is a radical here, I will say the domain is the radicand > or = 0.

So, x > or = 0.

Yes?
 
Last edited:
Mathematics news on Phys.org
RTCNTC said:
Precalculus by David Cohen, 3rd Edition
Chapter 1, Section 1.3.
Question 3b.

Specify the domain.

ax^(1/3) + b

Solution:

x^(1/3) means the cube root of x.

Since there is a radical here, I will say the domain is the radicand > or = 0.

So, x > or = 0.

Yes?

as cube root is defined for all real number (-ve number also) so the domain is set of real numbers
 
You are right. I found the following definition online:

"The domain of a cube root function is the set of all real numbers. Unlike a square root function which is limited to nonnegative numbers, a cube root can use all real numbers because it is possible for three negatives to equal a negative."
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Back
Top