What is the domain for variables with cube roots?

  • Context: MHB 
  • Thread starter Thread starter mathdad
  • Start date Start date
  • Tags Tags
    Domain
Click For Summary
SUMMARY

The discussion clarifies the domains of two expressions involving cube roots. For the expression ax + b, the domain is all real numbers (R), as there are no restrictions on x. In contrast, for the expression ax^(1/3) + b, the domain is also all real numbers, since cube roots can be calculated for both positive and negative values of x. The conclusion is that both expressions have a domain of R.

PREREQUISITES
  • Understanding of real numbers and their properties
  • Knowledge of cube roots and their mathematical implications
  • Familiarity with algebraic expressions and functions
  • Basic concepts of domain in mathematics
NEXT STEPS
  • Study the properties of cube roots in depth
  • Explore the concept of domains in various mathematical functions
  • Learn about the differences between even and odd roots
  • Investigate real number operations and their implications in algebra
USEFUL FOR

Students, educators, and anyone interested in algebraic functions and their domains, particularly those studying real numbers and cube roots.

mathdad
Messages
1,280
Reaction score
0
Specify the domain of each variable.

1. ax + b

Here x can be any integer.

In that case the domain is R, where R is ALL REAL NUMBERS.

2. ax^(1/3) + b

Let x^(1/3) be the cube root of x.

Let D = domain

x^(1/3) is > or = 0

[x^(1/3)]^3 > or = 0^(1/3)

x > or = 0

D = {x| x > or = 0}

Is any of this right?
 
Physics news on Phys.org
RTCNTC said:
Specify the domain of each variable.

1. ax + b

Here x can be any integer.

In that case the domain is R, where R is ALL REAL NUMBERS.

Correct, there would be no restriction we would need to impose on $x$.

RTCNTC said:
2. ax^(1/3) + b

Let x^(1/3) be the cube root of x.

Let D = domain

x^(1/3) is > or = 0

[x^(1/3)]^3 > or = 0^(1/3)

x > or = 0

D = {x| x > or = 0}

Is any of this right?

Let's think about this...what is the cube of a negative number?
 
Negative numbers can't have real number square roots, but negative numbers can have real number cube roots.

Sample: (-8)^(1/3) = -2

Back to my question.

(x)^(1/3) is the cube root of x. The domain can be any real number.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 8 ·
Replies
8
Views
3K