MHB What is the Domain of 1/x and 1/[(x - 1)(x + 2)(x - 3)]?

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The domain of the function 1/x is all real numbers except 0, expressed as {x|x cannot be 0}. For the function 1/[(x - 1)(x + 2)(x - 3)], the domain excludes the values where the denominator equals zero, specifically x = 1, -2, and 3. Thus, the correct domain is {x|x cannot be 1, -2, 3}. A typo was noted in the discussion, where -1 was incorrectly mentioned instead of -2. Overall, understanding the domain is crucial for determining where these functions are defined.
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Specify the domain of each variable.

1. 1/x

Here x can be any number EXCEPT for 0.

Domain = {x|x CANNOT be 0}

2. 1/[(x - 1)(x + 2)( x - 3)]

Set each factor to 0 and solve for x individually.

x - 1 = 0

x = 1

x + 2 = 0

x = -2

x - 3 = 0

x = 3

Let D = domain

D = {x|x CANNOT be 1, -1, 3}

Correct?
 
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RTCNTC said:
Specify the domain of each variable.

1. 1/x

Here x can be any number EXCEPT for 0.

Domain = {x|x CANNOT be 0}

2. 1/[(x - 1)(x + 2)( x - 3)]

Set each factor to 0 and solve for x individually.

x - 1 = 0

x = 1

x + 2 = 0

x = -2

x - 3 = 0

x = 3

Let D = domain

D = {x|x CANNOT be 1, -1, 3}

Correct?

right but there is a typo error D = $\{x|x\, cannot\, be \, be\, 1, -2, 3\}$
 
Yes, I made a typo which is a very common mistake using the cell phone keyboard.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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