What is the drill's angular acceleration?

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SUMMARY

The discussion centers on calculating the angular acceleration of a high-speed drill that rotates counterclockwise at 2200 RPM and comes to a halt in 2.80 seconds. The key equation used is α = (ω_f - ω_i) / t, where ω_f is the final angular velocity (0 rad/s) and ω_i is the initial angular velocity calculated as 232.71 radians per second. The user initially struggled with the radius (r) but later recognized that it was unnecessary for determining angular acceleration in this context. The solution confirms that the drill's angular acceleration is derived directly from the change in angular velocity over time.

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Homework Statement



A high-speed drill rotating ccw at 2200rpm comes to a halt in 2.80 s. What is the drill's angular acceleration?

Homework Equations



(where w = angular velocity)
w = 2╥/T
v = wr
a = v^2/r
a = w^2*r

The Attempt at a Solution



I start by calculating w. So first I took it to rev per second and then second per revolution which came to be 0.027 seconds per revolution. So w = 2╥/0.027 = 232.71 radians. Now I'm stuck because I don't have r (radius). I've tried going backwards to get r from v, but to no success since v depends in r as r depends in v. Every equation relating to acceleration seems to need r but I don't see how I can get it. Any ideas would be appreciated. Thanks.
 
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you don't need radius or linear velocity.

\alpha = \frac{\omega_f - \omega_i}{t}
 
Thank you. I realized after you posted that equation that it was a nonuniform circular motion problem, I was going about it the wrong way.
 

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