What is the Effect of Connecting a Load on the Polarity of Induced Voltage?

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SUMMARY

The discussion centers on the effect of connecting a load to an open-circuited loop in a magnetic field, specifically addressing the polarity of induced voltage. The participant asserts that connecting a load reverses the polarity of the electric field, contrary to the consensus that the polarity remains unchanged. The relevant equation, Curl E = -dB/dt, is cited to support the analysis of the induced electric field's behavior in response to a changing magnetic field.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with Maxwell's equations, particularly Curl E = -dB/dt
  • Knowledge of electric fields and current density relationships
  • Basic concepts of circuit theory and load connections
NEXT STEPS
  • Study the implications of Faraday's Law of Induction
  • Explore the relationship between electric fields and magnetic fields in detail
  • Investigate the effects of load on induced voltage in various circuit configurations
  • Learn about the behavior of electric fields in dynamic systems
USEFUL FOR

Students of electromagnetism, electrical engineering majors, and anyone studying the principles of induced voltage and circuit behavior.

johnstamos
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Homework Statement



This is seriously going to drive me insane. I know that a time changing B field produces a curling E field. For case #1, I have an open circuited loop with a B field increasing out of the page. This should create a polarity indicated in my picture.

I hook up a load to it. I have an electric field curling in the clockwise direction, E is proportional to current density, and so the polarity across the terminals should be reversed.

And yet my prof/all other people keep telling me that the polarity stays the same. So by connect a load, we actually reverse the direction of the electric field?

Homework Equations



Curl E = -dB/dt;

The Attempt at a Solution



see above


https://dl-web.dropbox.com/get/Public/Photo%20Feb%2025%2C%201%2053%2009%20AM%20%281%29.jpg?w=e2e0f3fc
 
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