What is the electric potential derivative when x=2 and y=1?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 2K views
IslandHead
Messages
9
Reaction score
0

Homework Statement

The electrical potential can be described by the following equation:
V= 200/(x2 + y2 )1/2 find dV when x=2 and y=1


Homework Equations


n/a


The Attempt at a Solution


dv/d(x,y) = ∂/∂x + ∂/∂y
=200/(x2 + y2)(1/2) +200/(x2 + y2)(1/2)
replace variables with C where necessary and rearrange for easy of deriving =200(x2 + C)(1/2) +200(C + y2)(1/2)
Chain rule and exponent rule
=200(-1/2)(2x)(x2 + C)(-3/2) +200(-1/2)(2y)(C + y2)(-3/2)
=-200x(x2 + C)(-3/2) + -200y)(C + y2)(-3/2)
=-200x(x2 + y2) )(-3/2) + -200y)(x2+ y2)(-3/2)
Then I plug in the values x=2 and y=1 and dV=-53.7 V/m, I'm not very confident with multivariable calculus and just wanted to check to see if this is right.
 
Last edited:
Physics news on Phys.org