1. The problem statement, all variables and given/known data What is the electric potential energy of a proton located 20.0 A (one angstrom or 1A is equal to 10^-10m) from another proton? 2. Relevant equations Ep= F x d F= kq1q2/r^2 3. The attempt at a solution Ep= Fxd F=kq1q2/r^2 therefore Ep = (Kq1q2)(d)/r^2 d=r so Ep= KQ1Q2/r (9x10^9)(1.60x10^-19)(1.60x10^-19)/(20x10^-10) = 1.152x10^-19J Help me check see if i got it right please!