What is the electric potential energy of a proton

[Jabababa]

Homework Statement

What is the electric potential energy of a proton located 20.0 A (one angstrom or 1A is equal to 10^-10m) from another proton?

Homework Equations

Ep= F x d
F= kq1q2/r^2

The Attempt at a Solution

Ep= Fxd
F=kq1q2/r^2

therefore Ep = (Kq1q2)(d)/r^2
d=r
so Ep= KQ1Q2/r

(9x10^9)(1.60x10^-19)(1.60x10^-19)/(20x10^-10)
= 1.152x10^-19J

Help me check see if i got it right please!

 

[ap123]

Your answer looks right :)
It would be easier to directly use the formula for the potential energy rather than starting with the force equation.

 

[rude man]

I second the response.