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breedb
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What is the electric potential energy in joules of two electrons separated by 2.68 nm?
What is the electric potential energy of two electrons separated by 2.68 nm?
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SUMMARY
The electric potential energy of two electrons separated by 2.68 nm is calculated using the formula U = k * (q1 * q2) / r, where k is Coulomb's constant (8.99 x 10^9 N m²/C²), q1 and q2 are the charges of the electrons (-1.6 x 10^-19 C), and r is the separation distance (2.68 x 10^-9 m). Substituting these values, the electric potential energy is approximately -1.07 x 10^-18 joules. This negative value indicates an attractive force between the two negatively charged electrons, consistent with electrostatic principles.
PREREQUISITES- Coulomb's Law
- Understanding of electric charge
- Basic knowledge of physics equations
- Familiarity with SI units
- Research the implications of electric potential energy in atomic interactions.
- Learn about the role of Coulomb's constant in electrostatics.
- Explore the concept of electric fields generated by point charges.
- Investigate the effects of distance on electric potential energy in multi-electron systems.
Physics students, educators, and anyone interested in electrostatics and the behavior of charged particles.
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