What is the Elevator's Acceleration Direction When the Scale Reads Higher?

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Homework Help Overview

The discussion revolves around a physics problem involving an object in an elevator, where the scale reads a higher weight than the object's actual weight. Participants are exploring the implications of this scenario on the acceleration of the elevator and the forces at play.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of forces and acceleration, questioning the readings of the scale and the nature of the forces involved. There are inquiries about the free body diagram and the forces acting on the object, including normal force and gravitational force.

Discussion Status

There is active engagement with various interpretations of the forces and the readings on the scale. Some participants suggest that the scale measures force while being marked in units of mass, leading to further questioning about the accuracy of the free body diagram and the forces exerted by the elevator.

Contextual Notes

Participants are navigating assumptions about the scale's measurements and the forces acting in the elevator system. There is a focus on understanding the relationship between mass, weight, and the readings provided by the scale in a non-standard context.

Quincy
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Homework Statement


An object weighs 65 kg. When it is in an elevator on a bathroom scale, the scale reads 82 kg. What is the acceleration of the elevator and what is its direction?


Homework Equations



FG = mg

The Attempt at a Solution



(82 kg)(9.8) = 803.6 N
803.6 N = (65 kg)(a)
a = 12.36

12.36 - 9.8 = 2.6 m/s2 upwards
 
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Quincy said:

Homework Statement


An object weighs 65 kg. When it is in an elevator on a bathroom scale, the scale reads 82 kg. What is the acceleration of the elevator and what is its direction?


Homework Equations



FG = mg

The Attempt at a Solution



(82 kg)(9.8) = 803.6 N
803.6 N = (65 kg)(a)
a = 12.36

12.36 - 9.8 = 2.6 m/s2 upwards

Is this a question?

Or a victory lap?

Looks ok to me.
 
Also, what would the free body diagram look like? Would there be a normal force upwards, and the gravitational force & the force from elevator pointing downwards?
 
Quincy said:
Also, what would the free body diagram look like? Would there be a normal force upwards, and the gravitational force & the force from elevator pointing downwards?
What are the scales that the object is sitting on actually measuring?
 
heth said:
What are the scales that the object is sitting on actually measuring?
They are measuring mass. I was also surprised by this since one would think they'd be measuring weight/Newtons... Anyways, is the free body diagram correct?
 
Quincy said:
They are measuring mass. I was also surprised by this since one would think they'd be measuring weight/Newtons... Anyways, is the free body diagram correct?

You could place the scales against a vertical wall and push on them horizontally. The scales would give a reading in kg. But would that have anything to do with mass? The mass of a push?! :-)

If you figure out how the scales actually work and what they are measuring, then you'll be able to figure out if the free body diagram is correct.
 
Quincy said:
Also, what would the free body diagram look like? Would there be a normal force upwards, and the gravitational force & the force from elevator pointing downwards?

There is the N force up and the m*(g + a) down.

The Scale is measuring force, but as nothing in life is ever so simple it's marked in units of mass weight, which is the way I think most people interact with mass.
 
LowlyPion said:
There is the N force up and the m*(g + a) down.

The Scale is measuring force, but as nothing in life is ever so simple it's marked in units of mass weight, which is the way I think most people interact with mass.

The normal force is upwards, the gravitational force is downwards, and (m)(a) is downwards? By (m)(a), do you mean the force of the elevator? Or is there no force from the elevator?
 
Quincy said:
The normal force is upwards, the gravitational force is downwards, and (m)(a) is downwards? By (m)(a), do you mean the force of the elevator? Or is there no force from the elevator?

The acceleration within the frame of reference of the elevator (the scene of the problem) is (g + a).
So m*(g + a) is the force it is exerting on the scale and the spring in the scale back upward.

If you want to draw force diagrams for the elevator then you need to know what its mass is as well as the mass of the objects in the elevator.
 

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