What is the EMC effect and how does it challenge conventional nuclear physics?

  • Thread starter Thread starter tzimie
  • Start date Start date
  • Tags Tags
    Nuclei Quarks
Click For Summary
SUMMARY

The EMC effect challenges conventional nuclear physics by demonstrating that treating the nucleus solely as a bound system of protons and neutrons is inadequate. Experimental observations from deep inelastic scattering (DIS) reveal a dip in the cross-section ratio between a nucleus and a deuteron in the range of 0.3 < x < 0.7, which cannot be explained by traditional models. Current computational methods in quantum chromodynamics (QCD) struggle with calculating nuclear properties, particularly for lighter elements, due to the exponential increase in complexity with particle count. The state of the art allows for approximate calculations of binding energies for helium isotopes, but further advancements are necessary to utilize pure QCD effectively.

PREREQUISITES
  • Understanding of quantum chromodynamics (QCD)
  • Familiarity with deep inelastic scattering (DIS)
  • Knowledge of nuclear physics, specifically the structure of protons and neutrons
  • Basic computational modeling techniques in particle physics
NEXT STEPS
  • Research the EMC effect and its implications on nuclear models
  • Explore advanced computational techniques in QCD for nuclear property calculations
  • Study the role of parton distribution functions (pdfs) in deep inelastic scattering
  • Investigate the current limitations and future directions in simulating quark interactions
USEFUL FOR

Physicists, nuclear researchers, and computational scientists interested in the complexities of nuclear interactions and the limitations of traditional nuclear models.

tzimie
Messages
256
Reaction score
27
Hi

Based on what I know (it might be wrong) properties of nuclei are calculated based on the different (simplified) models of the p and n "particles" (shells, droplets etc). I have 2 questions:

1. To what extent can we assume that n and p are "elementary" particles bound by residual strong force versus true picture on 3*(n+p) valence quarks and pure QCD? If we could calculate using both models - quark and hardon, what would be the level of inaccuracy of the simplified hardon model?

2. I've also heard that the computational complexity in QCD increases exponentially with the number of particles (when matter is cold enough). How far are is the current computational power (I don't mean a single computer, but huge networks like SETI@home, or power of video cards wasted on "mining bitcoins"). So how far is that power from being useful to calculate nuclear properties using "pure" QCD? May be not Uranium, but lighter elements?

Thank you
 
Physics news on Phys.org
I think you can assume (1) as long as you are below the QCD energy scale (~200MeV).
 
tzimie said:
2. I've also heard that the computational complexity in QCD increases exponentially with the number of particles (when matter is cold enough). How far are is the current computational power (I don't mean a single computer, but huge networks like SETI@home, or power of video cards wasted on "mining bitcoins"). So how far is that power from being useful to calculate nuclear properties using "pure" QCD? May be not Uranium, but lighter elements?

Calculating properties of nuclei from QCD is indeed very hard. I think the current state of the art is that we can approximately calculate the binding energies of helium-3 and helium-4 in an unphysical scenario where the up and down quarks are much heavier than they are in the real world. The cost of the simulation increases as the quark mass decreases, so it will take some effort to do even this simple nucleus at the lighter, physical values of the up and down quark masses. I don't know if it's at the right level, but you could take a look at this overview.
 
For (1) see ChrisVer.

tzimie said:
2. I've also heard that the computational complexity in QCD increases exponentially with the number of particles (when matter is cold enough). How far are is the current computational power (I don't mean a single computer, but huge networks like SETI@home, or power of video cards wasted on "mining bitcoins"). So how far is that power from being useful to calculate nuclear properties using "pure" QCD? May be not Uranium, but lighter elements?
They are still struggling with some mesons (-> XYZ spectroscopy) or precise ab initio mass predictions for individual baryons. Without effective models in some way, it is hard to do anything.
 
OMG, just for few quarks... So it is THAT bad...
Which means, that even we had TOE right now, we wouldn't be able to make any calculations->predictions, because near Planck energies we would have to take into account a cloud of all types of virtual particles, including quarks and gluons, all that QCD stuff.
 
At higher energies I think that it's possible to make QCD calculations, since the coupling constant gets smaller and so you can work with the 3 valance quarks (the sea quarks and gluons get to zero).
 
ChrisVer said:
At higher energies I think that it's possible to make QCD calculations, since the coupling constant gets smaller and so you can work with the 3 valance quarks (the sea quarks and gluons get to zero).

Yes and no. The sea quarks and gluons matter more and more at higher energies (see fig 16.4 in the PDG summary on structure functions http://pdg.lbl.gov/2011/reviews/rpp2011-rev-structure-functions.pdf). However, higher energies mean that the strong coupling constant is weaker, which means that you are further and further into the deep inelastic scattering (DIS) regime, where you can use perturbation theory to high accuracy - you just need to know the parton pdfs.
 
tzimie, regarding your first question: there is an experimental effect called the EMC effect where conventional nuclear physics (treating the nucleus as a bound system of protons and neutrons) is inadequate. If deep inelastic scattering (DIS)—and I recommend Orodruin's link on this—is performed on a nucleus, and on a deuteron, then the ratio of their cross sections, given as a function of Bjorken x, has a dip in the region 0.3<x<0.7 that cannot be explained simply by accounting for the motion or binding energy of nucleons.

For this reason, everyone seems to believe that calculations should be done with quarks and gluons in order to explain the EMC effect, but no-one really agrees on how.
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 19 ·
Replies
19
Views
5K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
7K
Replies
5
Views
4K