What is the empirical formula of this compound help?

  • Thread starter Larrytsai
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  • #1
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A hydrated substance was found to have the following percentage composition= Na 18.53%
S= 25.87%
O= 10.34%
H2O= 62.9%
What is the empirical formula of this compound?


what i got was Na2S2O3 - 5H2O
but im confused cause Na and S are both 0.806 mols
 

Answers and Replies

  • #2
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Perhaps, if you showed your work you might get more answers.
 
  • #3
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10.34/16 < 18.53/23 and 25.87/32, but you have more O atoms in your formula than Na and S. How is that? I got Na5S5O4*22H2O, but thats probably not right.
 
  • #4
228
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umm hmm i assumed 100 grams and then converted to mols
 
  • #5
93
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Use this cool poem.

Percent to mass
Mass to mole
Divide by small
Multiply 'til whole
Poem by "Joel S. Thompson"
 
  • #6
73
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Use this cool poem.

Percent to mass
Mass to mole
Divide by small
Multiply 'til whole
Poem by "Joel S. Thompson"

That's pretty neat! I'll have to remember that.
 
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