Determine the Empirical Formula of a compound which, when analyzed, is shown to consist of 62.07% carbon, 27.59% oxygen and 10.34% hydrogen.
The answer is supposedly C3OH6
The Attempt at a Solution
First,I started by writing the ratio: C : O : H
Then, under each, I wrote the respective percentages.
I divided everything by the lowest percentage (10.34), giving me a ratio of 6:2.668:1, (C6O3H).
I have no real idea of what to do or where I went wrong. Thanks so much for your help!