What is the energy of an X-ray photon with a wavelength of 6.6*10^–11 m?

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SUMMARY

The energy of an X-ray photon with a wavelength of 6.6 * 10–11 m is calculated to be 19 keV, as derived from the equation E = (h * c) / λ. In this context, h represents Planck's constant, c is the speed of light, and λ is the wavelength. The discussion highlights the necessity of using the elementary charge (e) in the formula E(ev) = (h * c) / (λ * e) to convert the energy into electronvolts (eV), a common unit in physics for measuring energy.

PREREQUISITES
  • Understanding of Planck's constant (h)
  • Knowledge of the speed of light (c)
  • Familiarity with the concept of wavelength (λ)
  • Basic comprehension of electronvolts (eV) and their relation to joules
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  • Study the derivation of the energy-wavelength relationship in quantum mechanics
  • Learn about the significance of electronvolts in particle physics
  • Explore the applications of X-ray spectroscopy in material analysis
  • Investigate the role of Planck's constant in quantum theory
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Students and professionals in physics, particularly those focusing on quantum mechanics, X-ray spectroscopy, and energy calculations in atomic physics.

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Homework Statement


The X-ray spectrum of molybdenum has a particular characteristic spectral line of
wavelength 6.6 *10^–11 m. The ionisation energy of molybdenum is 20 keV.

Deduce that the energy of an X-ray photon of wavelength 6.6*10^–11 m is 19 keV.


Homework Equations


E=h*f
E=(h*c)/l
h=planks constant
c=speed of light
l=lambda(wavelength)


The Attempt at a Solution


Normally this is quite easy. You just plug in wavelength into the equation and it should give you the answer. However, the part that I do not understand is that in the markscheme the proper formula to use is E(ev)=(h*c)/(l*e). Were e is elementary charge. Now this does not make sense to me as (h*c)/(l*e)=V (Voltage). So could someone explain why I need to use elementary charge.
 
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Physicists often use eV as unit for energy instead of joule. 1 eV is the energy an electron gains when it is accelerated across 1 V potential difference. This energy is equal to 1( V ) * e (charge of electron) = 1.6 10-19 J.

ehild
 

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