What is the equation of a circle tangent to the x-axis with a center at (3, 5)?

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The equation of a circle tangent to the x-axis with a center at (3, 5) is derived using the standard circle equation (x - h)² + (y - k)² = r². Here, h = 3, k = 5, and the radius r is equal to 5, as the circle is tangent to the x-axis. Therefore, the final equation is (x - 3)² + (y - 5)² = 25. This confirms the correct formulation of the circle's equation.

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Find the equation of the circle tangent to the x-axis and with center (3, 5).

(x - h)^2 + (y - k)^2 = r^2

h = 3, k = 5

r = 5

(x - 3)^2 + (y - 5)^2 = 5^2

(x - 3)^2 + (y - 5)^2 = 25

Yes?
 
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