MHB What is the equation of a circle tangent to the x-axis with a center at (3, 5)?

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The equation of a circle tangent to the x-axis with a center at (3, 5) is derived using the formula (x - h)^2 + (y - k)^2 = r^2. Here, h is 3, k is 5, and the radius r is equal to 5, as the distance from the center to the x-axis is 5. Substituting these values, the equation simplifies to (x - 3)^2 + (y - 5)^2 = 25. The calculations confirm the correctness of the equation. This demonstrates a clear understanding of the geometric properties of circles.
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Find the equation of the circle tangent to the x-axis and with center (3, 5).

(x - h)^2 + (y - k)^2 = r^2

h = 3, k = 5

r = 5

(x - 3)^2 + (y - 5)^2 = 5^2

(x - 3)^2 + (y - 5)^2 = 25

Yes?
 
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