What Is the Equation of State for a Gas Given Its Gibbs Function?

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Homework Help Overview

The discussion revolves around deriving the equation of state for a gas using its Gibbs function, as well as exploring thermodynamic properties of a spring under Hooke's law. The Gibbs function provided includes terms dependent on pressure and constants, prompting participants to analyze its implications for the gas's behavior. The second part of the problem involves determining free energy, internal energy, and entropy for a spring system, considering temperature dependence.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to derive the equation of state from the Gibbs function by equating differentials and exploring the implications of the derived expressions. Some participants question the simplicity of the results and the treatment of initial conditions in the spring problem, while others suggest examining the energy equations and their dependencies on temperature and displacement.

Discussion Status

Participants are actively engaging with the problem, offering insights and alternative perspectives. Some have provided guidance on how to approach the spring's energy equations, while others express uncertainty about handling initial conditions. The discussion reflects a mix of interpretations and attempts to clarify the relationships between the variables involved.

Contextual Notes

There are mentions of specific initial conditions that need to be addressed in the context of the spring problem, which may affect the overall analysis. Additionally, the treatment of temperature dependence in the equations is under scrutiny, indicating potential constraints in the problem setup.

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Homework Statement


*1* The Gibbs function G(T; P) of a certain gas is:
G = nRT ln P + A + BP + (1/2)*CP^2 + (1/3)DP^3

where A, B, C and D are constants. Find the equation of state of the gas.

Homework Equations



G = nRT ln P + A + BP + (1/2)*CP^2 + (1/3)*DP^3

The Attempt at a Solution



I think I have a solution for this, but it seemed to be too easy.

The definition for Gibbs free energy is defined to be:
1) G = U - TS + PV and 2) dG = -SdT + vdP

solving 2) for dG/dP yields: dG/dP = -SdT/dP + V 3)

I thought to take 3) at constant temperature yielding: dG/dP = V
Now, taking dG/dP at constant T from the given formula yields:

dG/dP =nRT/P + B + CP + DP^2 4)

Setting 3) = 4) and solving for PV yields:

PV = nRT + PB + CP^2 + DP^3
That just seemed too easy for me >.>
The second part of this homework is:

Homework Statement


Consider a spring which follows Hookes law; namely the displacement x from equilibrium
position is proportional to the tension X when it is pulled at a constant temperature. The spring constant is temperature dependent, k = k(T). Determine the free energy F, the internal energy U, and the entropy S, as a function of T and x. Neglect the thermal expansion of spring. Use F0(T) ´ F(T; x = 0); U0(T) ´ U(T; x = 0); S0(T) ´ S(T; x = 0) where necessary.

Homework Equations



k = k(T)
F[0](T) = F(T; x = 0)
U[0](T) = U(T; x = 0)
S[0](T) =S(T; x = 0)

where the brackets denote subscripts

The Attempt at a Solution



The force of the spring can be obtained by: F = -k(T) * x
And the work: W = int(-k(T) * x) dx = -(1/2)*k(T)*x^2

and dW = k(T) *xdx

Using the first law of thermodynamics: dU = dQ - dW, so

dU = dQ + k(T)*xdx
 
Last edited:
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The elongation of the spring would add another term to your energy equation:

U=TS-PV+Fx=TS-PV+k(T)x^2

F=U-TS=-PV+k(T)x^2

S=-\left(\frac{\partial F}{\partial T}\right)_V=-\frac{\partial k(T)}{\partial T} x^2

Does this help?
 
That makes sense to me, but what about those 3 initial conditions? This just seems too easy to me >.>

F[0](T) = F(T; x = 0)
U[0](T) = U(T; x = 0)
S[0](T) =S(T; x = 0)

What do I do with those?
 
I cheated a bit by ignoring the temperature dependence of PV and by setting my energy baseline at \mu\,N. The initial conditions make these constants go away anyway. Wouldn't you end up with, for example,

S=S_0-\frac{\partial k(T)}{\partial T} x^2

I'll leave the rest for you.
 
Thanks a bunch! This helps a lot! :P
 

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