What is the Equilibrium Constant for the Reaction Between PbCl2 and Ag+?

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SUMMARY

The equilibrium constant (Kc) for the reaction between lead(II) chloride (PbCl2) and silver ions (Ag+) can be calculated using the provided Kc values for the relevant reactions. The Kc for the dissociation of PbCl2 is 1.8 x 10-10, and for the formation of silver chloride (AgCl), it is 2.48 x 105. By combining these constants, the Kc for the reaction of PbCl2 with Ag+ is determined to be 7.2 x 10-16, confirming that the reaction is indeed solvable.

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Miike012
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Given the following reaction data at 25oC,
PbCl2  Pb+2 + 2Cl- Kc = 1.8*10-10
2Ag+ + 2Cl-  2AgCl Kc = 2.48*105
Calculate Kc for the reaction of PbCl2 and Ag+.
a. 7.2*10-16
b. 1.4*1015
c. 4.4*105
d. 4.5*10-5
e. can not solve

Is this solveable? I don't know where to start>?
 
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Start writing reaction equation and all Kc formulas. If you were not ignoring template, you would have it ready.
 

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