What is the equivalent capacitance for this circuit?

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Homework Help Overview

The discussion revolves around determining the equivalent capacitance of a circuit. Participants are exploring the application of formulas for capacitors in series and parallel configurations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to identify which capacitors are in series and which are in parallel, discussing the need to simplify the circuit step by step. Questions are raised about specific components and their configurations within the circuit.

Discussion Status

There is ongoing exploration of how to approach the problem, with some participants offering suggestions on simplifying the circuit. Multiple interpretations of the circuit layout are being discussed, and some guidance has been provided regarding the identification of series components.

Contextual Notes

Participants are working with attachments that illustrate their attempts and the original circuit, but there is mention of potential confusion regarding the arrangement of components. The discussion reflects a collaborative effort to clarify the setup and reasoning behind the calculations.

KeithLucas
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Homework Statement



I'm trying to find the equivalent capacitance for a circuit, but I keep getting stuck.

Homework Equations


C(parallel)=C1+C2+...Cn
C(series)={(1/C1)+(1/C2)+(1/C3)+...(1/Cn)}^-1


The Attempt at a Solution


See the first penciled attachment.
 

Attachments

  • CCF11142012_0000.jpg
    CCF11142012_0000.jpg
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  • CCF11142012_0002.jpg
    CCF11142012_0002.jpg
    8.6 KB · Views: 473
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KeithLucas said:

Homework Statement



I'm trying to find the equivalent capacitance for a circuit, but I keep getting stuck.

Homework Equations


C(parallel)=C1+C2+...Cn
C(series)={(1/C1)+(1/C2)+(1/C3)+...(1/Cn)}^-1


The Attempt at a Solution


See the first penciled attachment.

I would start by solving everything that is in series with no junctions in between. That should clean it up a bit. If you still have trouble, post your drawing again after doing that.
 
superdave said:
I would start by solving everything that is in series with no junctions in between. That should clean it up a bit. If you still have trouble, post your drawing again after doing that.

Which ones are in series with no junctions in between? I've posted the original circuit in one attachment, but another attachment has my attempt where I thought I solved everything in series.
 
KeithLucas said:
Which ones are in series with no junctions in between?
Top and top left.
 
KeithLucas said:

Homework Statement



I'm trying to find the equivalent capacitance for a circuit, but I keep getting stuck.

Homework Equations


C(parallel)=C1+C2+...Cn
C(series)={(1/C1)+(1/C2)+(1/C3)+...(1/Cn)}^-1

The Attempt at a Solution


See the first penciled attachment.

your penciled attempt work out to be 3μF, which is same as mine and i think it is correct.
 
Last edited:

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