What is the equivalent capacitance for this circuit?

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SUMMARY

The discussion focuses on calculating the equivalent capacitance of a circuit using established formulas. The key equations referenced are C(parallel) = C1 + C2 + ... + Cn for parallel capacitors and C(series) = {(1/C1) + (1/C2) + (1/C3) + ... + (1/Cn)}^-1 for series capacitors. Participants emphasize the importance of identifying capacitors in series without junctions to simplify calculations. The final equivalent capacitance calculated is 3μF, which is confirmed as correct by multiple contributors.

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KeithLucas
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Homework Statement



I'm trying to find the equivalent capacitance for a circuit, but I keep getting stuck.

Homework Equations


C(parallel)=C1+C2+...Cn
C(series)={(1/C1)+(1/C2)+(1/C3)+...(1/Cn)}^-1


The Attempt at a Solution


See the first penciled attachment.
 

Attachments

  • CCF11142012_0000.jpg
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KeithLucas said:

Homework Statement



I'm trying to find the equivalent capacitance for a circuit, but I keep getting stuck.

Homework Equations


C(parallel)=C1+C2+...Cn
C(series)={(1/C1)+(1/C2)+(1/C3)+...(1/Cn)}^-1


The Attempt at a Solution


See the first penciled attachment.

I would start by solving everything that is in series with no junctions in between. That should clean it up a bit. If you still have trouble, post your drawing again after doing that.
 
superdave said:
I would start by solving everything that is in series with no junctions in between. That should clean it up a bit. If you still have trouble, post your drawing again after doing that.

Which ones are in series with no junctions in between? I've posted the original circuit in one attachment, but another attachment has my attempt where I thought I solved everything in series.
 
KeithLucas said:
Which ones are in series with no junctions in between?
Top and top left.
 
KeithLucas said:

Homework Statement



I'm trying to find the equivalent capacitance for a circuit, but I keep getting stuck.

Homework Equations


C(parallel)=C1+C2+...Cn
C(series)={(1/C1)+(1/C2)+(1/C3)+...(1/Cn)}^-1

The Attempt at a Solution


See the first penciled attachment.

your penciled attempt work out to be 3μF, which is same as mine and i think it is correct.
 
Last edited:

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