What is the equivalent of Electric P.E. in Magnetism?

Click For Summary
SUMMARY

The discussion centers on the analogy between electric and magnetic potentials, specifically addressing the absence of magnetic monopoles and the implications for deriving magnetic potential energy formulas. The scalar potential in magnetostatics is defined as Vm=(μ0/4π)Ω⋅I, where I is the current and Ω is the solid angle. The relationship B=-∇Vm parallels the electric field's relationship with electric potential, E=-∇V. However, due to the lack of magnetic charge, a direct equivalent to electric potential energy cannot be established, although magnetic potential energy can be calculated using the vector potential.

PREREQUISITES
  • Understanding of electromagnetic theory, particularly Maxwell's Equations.
  • Familiarity with scalar and vector potentials in electromagnetism.
  • Knowledge of magnetic fields and their properties, including magnetic dipole moments.
  • Basic calculus, particularly gradient and curl operations.
NEXT STEPS
  • Study the derivation of magnetic scalar potential and its applications in magnetostatics.
  • Explore the concept of magnetic vector potential and its relationship to magnetic fields.
  • Investigate the implications of magnetic monopoles in theoretical physics.
  • Learn about energy stored in magnetic fields and the formulas used to calculate it.
USEFUL FOR

Students and professionals in physics, particularly those specializing in electromagnetism, electrical engineers, and researchers exploring theoretical physics concepts related to magnetic fields.

userunknown
Messages
11
Reaction score
0
There is an analogy between electric and gravitational potential energy.
## U_g = \frac {GmM}{r}##
## U_e = \frac {kqQ}{r}##

What is the analogous formula in magnetostatics?

Thanks...
 
Physics news on Phys.org
No.Not exactly. Since magnetic monopoles do not exist as such then a similar equation would be hard to get. But we can define a scalar potential which depends on the current loop producing the field such that B=-Vm (Like E = -V) where Vm=(μ0/4π)Ω⋅I and I is the current of the loop producing the field and Ω is the solid angle that the loop subtends at the field point where we wish to determine B. You should find a derivation in any intermediate EM text.
 
If magnetic monopoles did exist, then there would be a symmetry between electric and magnetic potentials.

If I understand it correctly, in theory magnetic monopoles could exist, or perhaps should exist, but all observations so far show no evidence that they do exist in this universe.
 
gleem said:
No.Not exactly. Since magnetic monopoles do not exist as such then a similar equation would be hard to get. But we can define a scalar potential which depends on the current loop producing the field such that B=-Vm (Like E = -V) where Vm=(μ0/4π)Ω⋅I and I is the current of the loop producing the field and Ω is the solid angle that the loop subtends at the field point where we wish to determine B. You should find a derivation in any intermediate EM text.
This is confusing. You said: magnetic scalar potential is analogous with electric potential.
But some sources say: magnetic vector potential is analogous with electrical potential.

Thanks for the answer but which one is true?
 
I mean it in the sense of Maxwells Equations:

upload_2015-4-10_18-15-30.png


Where ρ is electric charge density in the first equation and ρ is magnetic charge density in the second equation. The equations look symmetrical in that case, but it just happens that magnetic charge density is zero.
 

Attachments

  • upload_2015-4-10_18-15-3.png
    upload_2015-4-10_18-15-3.png
    712 bytes · Views: 509
userunknown said:
But some sources say: magnetic vector potential is analogous with electrical potential.

Thanks for the answer but which one is true?

I used analogous in the manner that the magnetic scalar potential is related to the magnetic field through the gradient of a potential as is the electric field. The Vector potential obviously is a vector and is related to the magnetic field via a different vector operator i.e. the Curl. The difference between the two magnetic potentials is that the scalar potential is limited to points outside a conductor while the vector potential is not (like the electric potential). I don't think there is a particular question of truth or falsity about this issue. As I said originally "No. not exactly" because there is not an identical function for a magnetic field compared to an electric field since there is no magnetic charge.
 
  • Like
Likes   Reactions: userunknown
gleem said:
I used analogous in the manner that the magnetic scalar potential is related to the magnetic field through the gradient of a potential as is the electric field. The Vector potential obviously is a vector and is related to the magnetic field via a different vector operator i.e. the Curl. The difference between the two magnetic potentials is that the scalar potential is limited to points outside a conductor while the vector potential is not (like the electric potential). I don't think there is a particular question of truth or falsity about this issue. As I said originally "No. not exactly" because there is not an identical function for a magnetic field compared to an electric field since there is no magnetic charge.
Thank you.

I have just one more question. Can we derive magnetic potential energy formula from magnetic scalar potential, like we can do in electrostatics?

I'm searching this topic, I have seen this formula, as magnetic potential formula:
$$ U = -\vec m\cdot \vec B $$
Can we derive this potential energy formula from scalar potential?

Thanks again for help...
 
userunknown said:
I'm searching this topic, I have seen this formula, as magnetic potential formula:
U=−m⃗ ⋅B⃗​
U = -\vec m\cdot \vec B
Can we derive this potential energy formula from scalar potential?

U = - M⋅B is specific for a magnetic dipole moment in a magnetic field just like the potential energy for an electric dipole moment U= - p⋅E in an electric field.

The actual energy stored in a magnetic field is

Wm = (1/2⋅μ0) ∫v B2

while that for an electric field is

We = (ε0/2) ∫v E2
 
gleem said:
U = - M⋅B is specific for a magnetic dipole moment in a magnetic field just like the potential energy for an electric dipole moment U= - p⋅E in an electric field.

The actual energy stored in a magnetic field is

Wm = (1/2⋅μ0) ∫v B2

while that for an electric field is

We = (ε0/2) ∫v E2

But if we take Vm=(μ0/4π)Ω⋅I as a potential, based on the analogy between B=-Vm and E = -V, there must be a magnetic potential energy formula based on magnetic scalar potential(Vm=(μ0/4π)Ω⋅I) . Right?
 
  • #10
Actually not. At lest not to my knowledge. The derivation of Ue assumes an electric charge, so since there is no magnetic charge the derivation for magnetic PE cannot include any self energy of a "charge " distribution using Vm. However you can calculate a PE of a magnetic field using the vector poteriial since this can include the current distribution like the Ve does for the charge distribution in the electric PE.
 
  • Like
Likes   Reactions: userunknown
  • #11
gleem said:
As I said originally "No. not exactly" because there is not an identical function for a magnetic field compared to an electric field since there is no magnetic charge.

As an aside, there actually is. But it takes a little cheating, and then the non-physical magnetic charge has to be gauged-away. This is accomplished with a complex vector potential.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 15 ·
Replies
15
Views
5K
  • · Replies 3 ·
Replies
3
Views
1K