jacobi1
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Find the exact value of $$\sin \frac{\pi}{180}$$.
The exact value of $$\sin \frac{\pi}{180}$$, which is equivalent to $$\sin 1^\circ$$, can be derived using the cubic equation $$4x^3 - 3x + \tfrac{1}{16}\Bigl(2(1-\sqrt{3})\sqrt{5+\sqrt{5}} + \sqrt{2}(\sqrt{5}-1)(\sqrt{3}+1) \Bigr) = 0$$. This equation can be solved using Vieta's method, yielding the smallest positive root as the imaginary part of $$\sqrt[3]{ \frac{a+b}{4}}$$, where $$a$$ and $$b$$ are defined in terms of nested radicals. The discussion clarifies that the argument is in radians by convention when no degree symbol is present.
PREREQUISITESMathematicians, physics students, and anyone interested in advanced trigonometry and polynomial equations will benefit from this discussion.
Ummmmm...is the argument in radians or degrees? Kinda hard to tell given the fraction.jacobi said:Find the exact value of $$\sin \frac{\pi}{180}$$.
Start with the known formula for $\sin 3^\circ$ (you can find it here): $\sin 3^\circ = \frac1{16}\Bigl(2(1-\sqrt3)\sqrt{5+\sqrt5} + \sqrt2(\sqrt5-1)(\sqrt3+1) \Bigr).$ The formula $\sin(3\theta) = 3\sin\theta - 4\sin^3\theta$ then tells you that $\sin1^\circ$ is the smaller of the two positive roots of the cubic equation $$4x^3 - 3x + \tfrac1{16}\Bigl(2(1-\sqrt3)\sqrt{5+\sqrt5} + \sqrt2(\sqrt5-1)(\sqrt3+1) \Bigr) = 0,$$ which can be solved exactly, for example by Vieta's method. But don't expect a neat solution. (Emo)jacobi said:Find the exact value of $$\sin \frac{\pi}{180}$$ (in other words, $\color{red}{\sin 1^\circ}$).
By convention, if there is no degree symbol in the argument, it is in radians.topsquark said:Ummmmm...is the argument in radians or degrees? Kinda hard to tell given the fraction.
-Dan
Opalg said:Start with the known formula for $\sin 3^\circ$ (you can find it here): $\sin 3^\circ = \frac1{16}\Bigl(2(1-\sqrt3)\sqrt{5+\sqrt5} + \sqrt2(\sqrt5-1)(\sqrt3+1) \Bigr).$ The formula $\sin(3\theta) = 3\sin\theta - 4\sin^3\theta$ then tells you that $\sin1^\circ$ is the smaller of the two positive roots of the cubic equation $$4x^3 - 3x + \tfrac1{16}\Bigl(2(1-\sqrt3)\sqrt{5+\sqrt5} + \sqrt2(\sqrt5-1)(\sqrt3+1) \Bigr) = 0,$$ which can be solved exactly, for example by Vieta's method. But don't expect a neat solution. (Emo)