What is the exact value of the trig function for pi/180?

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Discussion Overview

The discussion centers around finding the exact value of the trigonometric function $$\sin \frac{\pi}{180}$$, which is equivalent to $$\sin 1^\circ$$. Participants explore various methods and formulas related to this calculation, including references to cubic equations and known sine values.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • Some participants seek the exact value of $$\sin \frac{\pi}{180}$$ without specifying a method.
  • One participant questions whether the argument is in radians or degrees, suggesting that the absence of a degree symbol implies radians by convention.
  • Another participant provides a formula for $$\sin 3^\circ$$ and derives a cubic equation for $$\sin 1^\circ$$, indicating that it can be solved exactly but may not yield a neat solution.
  • A later reply presents a method for solving the cubic equation, proposing a representation of the smallest positive solution in terms of cube roots involving square roots.
  • One participant humorously states that the exact value of $$\sin \frac{\pi}{180}$$ is simply $$\sin \frac{\pi}{180}$$.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the argument's units (radians vs. degrees). There are multiple approaches to finding the exact value of $$\sin 1^\circ$$, and no consensus is reached on a definitive method or solution.

Contextual Notes

Some methods rely on specific formulas and assumptions about the cubic equation derived from known sine values, which may not be universally accepted or understood.

jacobi1
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Find the exact value of $$\sin \frac{\pi}{180}$$.
 
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jacobi said:
Find the exact value of $$\sin \frac{\pi}{180}$$.
Ummmmm...is the argument in radians or degrees? Kinda hard to tell given the fraction.

-Dan
 
jacobi said:
Find the exact value of $$\sin \frac{\pi}{180}$$.

Just ask the Wolf. HERE
 
jacobi said:
Find the exact value of $$\sin \frac{\pi}{180}$$ (in other words, $\color{red}{\sin 1^\circ}$).
Start with the known formula for $\sin 3^\circ$ (you can find it here): $\sin 3^\circ = \frac1{16}\Bigl(2(1-\sqrt3)\sqrt{5+\sqrt5} + \sqrt2(\sqrt5-1)(\sqrt3+1) \Bigr).$ The formula $\sin(3\theta) = 3\sin\theta - 4\sin^3\theta$ then tells you that $\sin1^\circ$ is the smaller of the two positive roots of the cubic equation $$4x^3 - 3x + \tfrac1{16}\Bigl(2(1-\sqrt3)\sqrt{5+\sqrt5} + \sqrt2(\sqrt5-1)(\sqrt3+1) \Bigr) = 0,$$ which can be solved exactly, for example by Vieta's method. But don't expect a neat solution. (Emo)
 
Last edited:
Related with the OP (but more simple): http://www.fernandorevilla.es/ii/vi/58-2.
 
topsquark said:
Ummmmm...is the argument in radians or degrees? Kinda hard to tell given the fraction.

-Dan
By convention, if there is no degree symbol in the argument, it is in radians.
 
Opalg said:
Start with the known formula for $\sin 3^\circ$ (you can find it here): $\sin 3^\circ = \frac1{16}\Bigl(2(1-\sqrt3)\sqrt{5+\sqrt5} + \sqrt2(\sqrt5-1)(\sqrt3+1) \Bigr).$ The formula $\sin(3\theta) = 3\sin\theta - 4\sin^3\theta$ then tells you that $\sin1^\circ$ is the smaller of the two positive roots of the cubic equation $$4x^3 - 3x + \tfrac1{16}\Bigl(2(1-\sqrt3)\sqrt{5+\sqrt5} + \sqrt2(\sqrt5-1)(\sqrt3+1) \Bigr) = 0,$$ which can be solved exactly, for example by Vieta's method. But don't expect a neat solution. (Emo)

My method was exactly the same as yours, but I went ahead and solved the cubic. I found that the smallest positive solution can be written as the imaginary part of $$\sqrt[3]{ \frac{a+b}{4}}$$, where $$a=\sqrt{8+\sqrt{15}+\sqrt{3}+\sqrt{10-2 \sqrt{5}}}$$ and $$b=\sqrt{-8+\sqrt{15}+\sqrt{3}+\sqrt{10-2 \sqrt{5}}}$$. Conversely, the cosine of $$1^\circ$$ can be written as the real part of the above.
 
The exact value of \displaystyle \begin{align*} \sin{ \left( \frac{\pi}{180} \right) } \end{align*} IS \displaystyle \begin{align*} \sin{ \left( \frac{\pi}{180} \right) } \end{align*} :p
 

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