What is the final rotational speed of the double rotating disks?

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SUMMARY

The final rotational speed of the double rotating disks system can be calculated using the principle of conservation of angular momentum. The first disk, with a mass of 350 g and an initial speed of 152 rpm, has a moment of inertia of 0.00175 kg*m². The second disk, with a mass of 258 g and a radius of 5 cm, has a moment of inertia of 0.0003225 kg*m². By applying the conservation of angular momentum, the final speed (f_final) can be determined as the combined effect of both disks' initial angular momentum.

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Homework Statement


A disk of mass M1 = 350 g and radius R1 = 10 cm rotates about its symmetry axis at f_initial = 152 rpm. A second disk of mass M2 = 258 g and radius R2 = 5 cm, initially not rotating, is dropped on top of the first. Frictional forces act to bring the two disks to a common rotational speed f_final.
a) What is f_final? Please give your answer in units of rpm, but do not enter the units

Homework Equations


T = I*a
I = (m*r2)/2

The Attempt at a Solution


I found the moment of inertia of M1
I = (.5)(.35)(.12) = .00175 kg*m2
M2
I = (.5)(.258)(.052) = .0003225 kg*m2
I found the angular velocity [tex]\omega[/tex]
152rpm = 304pi rads/min = 5.06pi rads/sec
I don't suppose that I can just consider the mass to have just increased can I, because it specifies friction. I know some numbers, but how to put them together?
 
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You know that energy is not conserved because friction is acting and heat is being generated. However, something else is being conserved. What is it?
 
L = I*w and Li = Lf
Momentum would be conserved because the net torques act internally to the system. I get it, thanks for the hint.
 

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