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 Homework Statement:

The system has no slip
At first the system is resting and at some point we let m1 fall down. I need to find the forces (yellow arrows)
 Relevant Equations:

F = m*a
a = R*ß
torque = 1/2*m*R^2
Hi! I need help with this problem. m1234 and R are given. There is no slip in the system. I have to give F1234 in respect of the masses and R.
Here is what I managed to
m1 is easy: m1*a = m1*g  T(tension of the rope)
m2: m2*a = T  (???) < I have a problem with this. F1 and F3 is the Force on the wheels "made" by m2. But if m2 rotates the wheels, then m2's acceleration is weakened by the wheels, right? How? I need "new"(red arrows, not given by the teacher) forces acting on m2?
I can calculate the rotational forces on both wheels with this equation: Torque*angular acceleration = R*F(13)  R*F(24)
I can calculate the horizontal acceleration with this equation: m(34)* horizontal acceleration = F(13) + F(24)
I think the edge of the wheel had the same acceleration as m1 and m2, but I don't know how is it related to the horizontal acceleration.
I found an equation: a = R*angular acceleration, but if I am correct this isn't the acceleration of the rotating outer edge.
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