Calculating final temperature in insulated container

In summary, a sealed and insulated container contains 0.60kg of ice, 2.0kg of water, and 3kg of iron at different temperatures. The specific heats for each substance are given, as well as the latent heat for ice. The task is to find the final temperature inside the container. The equation used is Q=mcΔT, and after solving for Tf, the answer is incorrect. The missing factor in the calculation may be the ice, which would result in a different final temperature.
  • #1
Gaith
5
0

Homework Statement


0.60kg of ice at O degrees C, 2.0 kg of water at 0 degrees 0 degrees, 3kg of iron at 325 degrees C are place in a sealed and insulated container. The specific heat for iron is c=400J/kg degree C, for water is c=4200J/kgdegree, for water is c=4200J/kgdegree celcius, for ice is c=2000 and the latent heat for ice is 3.3x10^5J/kg.

What is the final temperature inside the insulated container

Homework Equations

[/B]
Q=mcΔT

The Attempt at a Solution


Q=0.6x2000(Tf)+2(4200)(Tf)+3x400(Tf-325) = 0
Q=1200Tf + 8400Tf + 1200Tf - 390000=0
I solved for Tf and got the wrong answer. Help me please.[/B]
 
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  • #2
Gaith said:

Homework Statement


0.60kg of ice at O degrees C, 2.0 kg of water at 0 degrees 0 degrees, 3kg of iron at 325 degrees C are place in a sealed and insulated container. The specific heat for iron is c=400J/kg degree C, for water is c=4200J/kgdegree, for water is c=4200J/kgdegree celcius, for ice is c=2000 and the latent heat for ice is 3.3x10^5J/kg.

What is the final temperature inside the insulated container

Homework Equations

[/B]
Q=mcΔT

The Attempt at a Solution


Q=0.6x2000(Tf)+2(4200)(Tf)+3x400(Tf-325) = 0
Q=1200Tf + 8400Tf + 1200Tf - 390000=0
I solved for Tf and got the wrong answer. Help me please.[/B]
It would help you and us if you would detail your calculations more carefully.

That said, what happens to the ice in the container after the hot iron is put in? It looks like you have taken care of the temp. change of the iron and the liquid water there initially, but the ice appears to be missing from your calculations. :L
 

1. How do you calculate the final temperature in an insulated container?

To calculate the final temperature in an insulated container, you need to use the formula Q = mcΔT, where Q is the heat gained or lost, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature. You also need to take into account any heat lost through the walls of the insulated container.

2. What is the specific heat capacity of a substance?

The specific heat capacity of a substance is the amount of heat required to raise the temperature of 1 gram of the substance by 1 degree Celsius. It is measured in joules per gram per degree Celsius (J/g°C). Specific heat capacity is different for each substance and can be found in reference tables.

3. How does the mass of the substance affect the final temperature in an insulated container?

The mass of the substance affects the final temperature in an insulated container because it is a factor in the heat capacity of the system. The more mass there is, the more heat is required to raise the temperature, and vice versa. This means that a larger mass will result in a lower final temperature, and a smaller mass will result in a higher final temperature.

4. Why is it important to take into account heat lost through the walls of an insulated container?

Heat lost through the walls of an insulated container can significantly affect the final temperature of the substance inside. This is because the walls act as a barrier between the inside and outside environment. If heat is lost through the walls, it means that the substance inside is losing heat and its temperature will decrease. Therefore, it is crucial to consider this factor in calculating the final temperature.

5. How does the initial temperature of the substance affect the final temperature in an insulated container?

The initial temperature of the substance can affect the final temperature in an insulated container in two ways. If the initial temperature is higher than the desired final temperature, it will take longer for the substance to cool down to the final temperature. If the initial temperature is lower than the desired final temperature, it will take longer for the substance to heat up to the final temperature. In both cases, the final temperature will ultimately be reached, but the time it takes to reach it will vary.

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