0.60kg of ice at O degrees C, 2.0 kg of water at 0 degrees 0 degrees, 3kg of iron at 325 degrees C are place in a sealed and insulated container. The specific heat for iron is c=400J/kg degree C, for water is c=4200J/kgdegree, for water is c=4200J/kgdegree celcius, for ice is c=2000 and the latent heat for ice is 3.3x10^5J/kg.
What is the final temperature inside the insulated container
The Attempt at a Solution
Q=0.6x2000(Tf)+2(4200)(Tf)+3x400(Tf-325) = 0
Q=1200Tf + 8400Tf + 1200Tf - 390000=0
I solved for Tf and got the wrong answer. Help me please.[/B]