1. The problem statement, all variables and given/known data 0.60kg of ice at O degrees C, 2.0 kg of water at 0 degrees 0 degrees, 3kg of iron at 325 degrees C are place in a sealed and insulated container. The specific heat for iron is c=400J/kg degree C, for water is c=4200J/kgdegree, for water is c=4200J/kgdegree celcius, for ice is c=2000 and the latent heat for ice is 3.3x10^5J/kg. What is the final temperature inside the insulated container 2. Relevant equations Q=mcΔT 3. The attempt at a solution Q=0.6x2000(Tf)+2(4200)(Tf)+3x400(Tf-325) = 0 Q=1200Tf + 8400Tf + 1200Tf - 390000=0 I solved for Tf and got the wrong answer. Help me please.