What Is the Focal Length and Magnification in Multi-Lens Systems?

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Homework Help Overview

The discussion revolves around a multi-lens system involving two main problems: determining the focal length of a system of five lenses and calculating the magnification of an image formed by a light source placed at the focal point of a lens. The subject area is optics, specifically lens systems and image formation.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply the lens formula to find the focal length and magnification, expressing uncertainty about their reasoning. Some participants suggest using ray matrices for a general approach and agree with the original poster's interpretations of the problems.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's attempts. Some guidance has been offered regarding the focal length and the nature of light from a point source, but there is no explicit consensus on the correctness of the original poster's solutions.

Contextual Notes

The original poster mentions receiving feedback that several of their solutions were incorrect, indicating a potential misunderstanding of the concepts involved. There is also a request for additional resources to better understand the calculations related to multi-lens systems.

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Homework Statement



1)
I have five lenses with f=25 placed at distance 50 from each other, what is the focal length of this system?
2)
A light source is placed in the focal point of a lens with f=50, at d=600 a lens with f=400 is placed, at the focal point of the second lens the image is captured, what is the magnification?

Homework Equations



\frac{1}{A}+\frac{1}{B} = \frac{1}{F} is everything, I think...

The Attempt at a Solution



1) I think the light rays will converge 25 after the last lens because for lens 2 and 4: 1/-f + 1/b = 1/f → b=-∞ so the light is parallel with x-axis after these lenses. For lens 1,3,5: 1/∞ + 1/b = 1/f → b=f so the projection is in the middle and for the last lens 25 away.

2)
I'm thinking the light is parallel to x-axis after the first lens because 1/f +1/b =1/f →
b=∞ and then for the second lens 1/∞ + 1/b = 1/f → image in f, so no magnification has occurred.

------
It's not certain both of my solutions are wrong, but probably both are :(.
If someone has a link to info about how to calculate lens after lens that would be great, I can't goggle it since I don't know what this sort of problem is called and my book is terrible.no help.

I am very happy for any help I can get, so thanks in advance.
 
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1) Seems okay. If you wanted to do this generally you could use ray matrices.

2) Yeah, if I read it right, I agree here too.
 
First; thank you for looking at my problems. But I did these 2 problems + 2 other and was told 3 out of 4 were wrong so both solutions can't be correct.
 
Well, I didn't fully understand your response to question 1, but the equivalent focal length is definitely 25, which is what you got.

I think you are right about Q2 too. A point source in the focal point of an ideal lens will give collimated light. So at this point you could put another lens at the end of a football field, and you'd get the same thing. The weird thing about this question is that it an image is captured at the focal point of the second lens. The other weird thing is that in technical terms a point source is a delta function, a point that is infinitely narrow, so it doesn't really even make sense to talk about it's magnification.

Maybe you can get some elaboration from your teacher on problem two, and I could help once I know what he/she wants.
 

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