What is the force exerted by a football on a kicker's foot?

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SUMMARY

The force exerted by a football on a kicker's foot can be calculated using the impulse-momentum theorem. Given a football mass of 0.41 kg and a final speed of 37 m/s, the initial calculation yielded a force of approximately 1264.17 N. However, the correct force, accounting for direction and Newton's third law, is 3750 N. This discrepancy was resolved by recognizing the need for a negative sign to reflect the opposing forces involved.

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Homework Statement


A barefoot field-goal kicker imparts a speed
of 37 m/s to a football initially at rest.
If the football has a mass of 0.41 kg and the
time of contact with the ball is 0.012 s, what
is the force exerted by the ball on the kicker’s
foot?
Answer in units of N.

Homework Equations


F=ma

The Attempt at a Solution


F= .41 * (37/.012) = 1264.166667 N
Answer was wrong, wouldn't this obey Newtons third law?
Or am I overlooking something obvious? Please help!
 
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You need to think of impulse and momentum for this problem.
 
so would it be,
impulse = force x time
1264.16667 N / .012 s = ans?
 
no... why are u trying to solve for impulse when you have to determine force? what are your known and unknown variables? define them... Delta t = 0.012s, massball = ... and so on
 
after defining your variables see if you are famliar with the impulse momentum formula:

mvf - mvi = momentum (where vf = final velocity and vi = initial velocity)
impluse = Force*delta t

impulse = momentum... maybe you can go about solving from there
 
Following your advice and retrying everything I still come up with the same answer that the Force = m ΔV/t
 
hmmm. the answer sounds correct. who told you that the answer was wrong? maybe the answer is supposed to have a negative sign?
 
tim_lou said:
hmmm. the answer sounds correct. who told you that the answer was wrong? maybe the answer is supposed to have a negative sign?

I get the same answer as the OP. I agree that a negative sign may be needed, since it is equal and opposite to the force of the foot on the ball for Newton's third law.
 
It was just the negative sign! Thanks guys I was killing myself over this
 
  • #10
how did u solve for it?? anyone?? i have the same problem?
 
  • #11
Hey i just got it finally, the 37 is added to the 51.5 not subtracted due to it being in the opposite direction. The correct answer is 3750.
 

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