What is the force exerted by an object on a rope?

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SUMMARY

The discussion focuses on the dynamics of a man pulling an object via a rope on a frictionless surface, analyzing the forces and resulting velocities. The net force equations established are Fnet = ma, with T representing tension in the rope. The velocities of both the man and the object can be derived using kinematic equations, given that both start from rest and meet at the center of mass. The conclusion confirms that the force exerted by the object on the rope is equal to the force exerted by the man, both equal to F.

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Homework Statement


Man with mass M pulling with constant horizontal force F along a rope attached to object with mass m. Both the man and the object are on a frictionless surface and separated by distance D. When the man and object meet, what is the velocity of the object? Velocity of the man?


Homework Equations





The Attempt at a Solution


Fnet = ma
Assume motion inwards is positive.
T - F = Ma(subM)
T - F(subobject) = ma(object)

When I draw the free body diagram, what force does the object exert on the rope? How can I "classify" this force? There's no friction, so where would the force of the object come from?
 
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Since there is no external force acting on the system, the center of mass remains at rest.
Let r1 be the distance of M from c.m., and r2 be the distance of m from c.m. such that
Mr1 = mr2. And r1 + r2 = D.
Both man and mass experience equal and opposite force F.
The acceleration of man is a1 = F/M, and acceleration of mass is a2 = F/m. They meet at c.m.
Man and mass start from rest. So vi = 0.
Now using kinematic equation find v1 and v2.
 
Thanks, I wasn't sure if I could say the force on the man and force on the object both equal F.
 

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