What Is the Force Exerted by the Elbow on the Forearm?

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Homework Help Overview

The problem involves analyzing the forces acting on a forearm in a therapeutic context, specifically focusing on the force exerted by the elbow while lifting a weight. The scenario includes the weight of the forearm, the weight being lifted, and the forces from the biceps muscle.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the force exerted by the elbow by analyzing the vector components of the forces involved. They express uncertainty regarding the magnitude of one of the vectors and question their approach when encountering a negative value.

Discussion Status

Some participants have engaged in the discussion by suggesting the use of a diagram or free body diagram (FBD) to clarify the forces at play. The original poster has indicated progress in their understanding, noting that their answer was accepted by the software, but they still seek guidance on their reasoning process.

Contextual Notes

The original poster expresses concern about seeking help and emphasizes their effort to understand the problem before asking for assistance. There is a mention of specific angles and vector components that are critical to the problem setup.

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Homework Statement


A patient in therapy has a forearm tht weights 24.5 N and that lifts a 112.0 N weight. These two forces have direction vertically downward. The only other significant forces on his forearm come from the biceps muscle (which acts perpendicularly to the forearm) and the force at the elbow. If the biceps produces a pull of 232 N when the forearm is raised 43 degrees above the horizontal, find the magnitude and direction of the force that the elbow exerts on the forearm. (THE SUM OF THE ELBOW FORCE AND THE BICEPS FORCE MUST BALANCE THE WEIGHT OF THE ARM AND THE WEIGHT IT IS CARRYING, SO THE VECTOR SUM MUST BE 136.5 N upward.)



Homework Equations


Ok, there are three vectors.
VECTOR A: magnitude of 136.5 N, angle is 270, x comp: 0, y comp: -136.5
VECTOR B: magnitude of ? , angle is 43, x comp: ?, y comp: ?
VECTOR C: magnitude of 232 N, angle is 43 degrees west of north, x comp: 232sin43: 158.2; y comp: 232cos43 = 169.7.


The Attempt at a Solution



so, since I don't know know what the magnitude of B is, I did this:
136.5 - 169.7= -33.3 which would be the y component of vector B I am guessing. Then I did this:
Bsin43 = -33.3; but my magnitude is a negative. So... What should I do now?

Also, I really do not want to abuse this privilege of getting help from geniuses in physics, but I try my best and if I don't get it, then I ask. If you can just guide me in a path that will get me the answer, I will appreciate that. Thanks again.
 
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you have a diagram?
I would try to get it though without a diag.

Edit: Couldn't get it, so a FBD would be good!
 
Last edited:
Thanks for replying, I was close to the answer and the software accepted the answer, so thank you so much!
 
oohhh..k, np
 

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