What is the formula for calculating the average stopping force in this scenario?

Click For Summary
SUMMARY

The discussion centers on calculating the average stopping force experienced by a 68 kg man who drops from a height of 0.60 m and stops over a distance of 0.02 m. The initial calculation of average acceleration was determined to be 293.95 m/s², leading to a net force of 19988 N using the formula F=ma. However, participants clarified that the average stopping force should account for both the normal force exerted by the ground and the gravitational force acting on the man, which was overlooked in the initial calculations.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Knowledge of gravitational force calculations
  • Familiarity with concepts of normal force
  • Basic principles of kinematics
NEXT STEPS
  • Review the concept of normal force in physics
  • Study gravitational force calculations for different masses
  • Learn about energy conservation principles in free fall
  • Explore advanced kinematic equations for stopping distances
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and forces, as well as educators seeking to clarify concepts related to stopping forces and free fall dynamics.

physics19
Messages
10
Reaction score
0
A 68 kg man drops to a concrete patio from a window only 0.60 m above the patio. He neglects to bend his knees on landing, taking 2.0 cm to stop. What is the magnitude of the average stopping force?

-From this problem I have already found that the average acceleration is 293.95 m/s^2. I tried to find the average force by using the formula F=ma. F=68kg(293.95m/s^2)=199988 N. However that is not right. I need is a formula to compute the average stopping force. Thank you.
 
Physics news on Phys.org
Welcome to Physics Forums, physics19!

Your method looks good, but you have an extra factor of 10 for some reason.

Try multiplying 68 x 293.95 again.
 
Thank you.. I actually copied down the wrong number when I inputed the answer. I got 19988N as my answer but that is not correct. My friend came up with the same result too and both of us are scratching our heads because we are not sure why it is not the correct answer. I was thinking that there may actually be another force that I have to account for but am not sure.
 
physics19 said:
Thank you.. I actually copied down the wrong number when I inputed the answer. I got 19988N as my answer but that is not correct. My friend came up with the same result too and both of us are scratching our heads because we are not sure why it is not the correct answer. I was thinking that there may actually be another force that I have to account for but am not sure.
Yes, there is another force. The wording of the problem is a tad bit confusing, but it does ask for the stopping force, which I take as the normal force of the ground on the person, and not the net force, which you have calculated. The normal force acts up; what other force on the person acts down??
 
Okay, I might know what's going on now.

Acceleration x mass gives the net force acting on the man.

"Stopping force" refers to the force of the concrete/ground on the man. What other force also acts on him?
 
Redbelly98 said:
Okay, I might know what's going on now.

Acceleration x mass gives the net force acting on the man.

"Stopping force" refers to the force of the concrete/ground on the man. What other force also acts on him?

hmmm I am not sure... this is a very confusing problem that the teacher has asked us!
 
What force caused the man to drop in the first place?
 
the gravity.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 14 ·
Replies
14
Views
8K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 2 ·
Replies
2
Views
7K