What is the Formula for Calculating Torque While Digging?

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SUMMARY

The discussion centers on calculating torque while digging, specifically using the formula τ = F × d, where τ represents torque, F is the force applied, and d is the length of the arm or link. Participants emphasize the importance of understanding the parameters involved, such as the friction force between the digging tool and the material being excavated. A practical approach suggested includes equating the torque applied by the user at the shovel's head with the torque due to gravity acting on the shovel.

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Homework Statement



Hi!

I want to calculate the torque acting on an arm while it is digging something. I only have the formula tau= Fxd. Anyone that know a good formula for this?

Homework Equations





The Attempt at a Solution


tau= Fxd, where d is the length of the link. I can't go any further
 
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ExoP said:
I want to calculate the torque acting on an arm while it is digging something. I only have the formula tau= Fxd. Anyone that know a good formula for this?
First start with a diagram
 
Can you explain a little more? what are the parameters? :/
 
I guess I need the friction force between the sand and the tool
 
ExoP said:

Homework Statement




I want to calculate the torque acting on an arm while it is digging something. I only have the formula tau= Fxd. Anyone that know a good formula for this?

The Attempt at a Solution


tau= Fxd, where d is the length of the link. I can't go any further[/QUOTE

If right-handed you could assume the pivot point is the right hand, the torque is applied where the left hand holds the shovel, then equate that torque with the torque applied by gravity at the shovel's head.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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