- #1

checkmatescott

- 80

- 2

## Homework Statement

hi my question is that say if rod of length l is 3m and is 90 degrees from horizontal pointing upwards with 2 kg weight on the end then there will be no torque produced because the force of gravity is acting parallel to the lever arm if the angle theta is 80 degrees then the torque would be weight force x l sin theta giving the lever arm x and if the rod was horizontal then the torque would be the weight force x l because the weight force would be acting perpendicular to the lever arm ie its maximum length i think i have to take an integral but I am not sure how i know that the torque increases as x increases but i don't know how to do it I am really stuck i want to find the total net torque as the weight moves around the quarter circle can anybody help it would be much appreciated thanks in advance i can provide a diagram if that would help you to get what I am talking about

#### Attachments

Last edited: