How Is Torque Calculated in This Physics Problem?

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SUMMARY

The calculation of torque in the discussed physics problem is based on the formula T = fxd, where T represents torque, f is the force applied, and d is the distance from the pivot point. The total torque calculated is 980 Nm, assuming the weight is applied correctly at a distance of 1 meter from the axle. The discussion emphasizes that torque direction is influenced by the placement of weight, with counterclockwise and clockwise rotations depending on whether weight is added to the left or right side of the axle, respectively. Clarification on the torque application point is also provided, indicating that torque can be calculated about any chosen pivot point, specifically the center of the axle in this scenario.

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Pinon1977
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Homework Statement

, [/B]
Please see the attached picture. But I'm trying to do is figure out where this moment would be created and how much torque would be applied based upon this example.

Homework Equations


T = fxd

The Attempt at a Solution

[/B]
I would suspect that any weight added to the left side of the axle would be pushing the system in a counterclockwise fashion. And, conversely, I need weight added on the right side of the axle wood have a tendency to counter that by pushing the axle in a clockwise fashion. I believe the total torque to be:
980 Nm
 

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Pinon1977 said:
I believe the total torque to be:
980 Nm
If your diagram is accurate, yes, but it looks odd that in spite of the lever arm being rotated to some unspecified angle to the horizontal the weight is exactly 1m horizontally from the axle. Maybe you shoukd post the original question exactly as given to you.

Your question about where exactly the torque is applied suggests some misunderstanding. The torque applies at whichever point you chose to calculate it about; in this case, the centre of the axle.
 

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