What is the Formula for Converting Rotational Speed to Linear Speed?

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The discussion focuses on the formula for converting rotational speed to linear speed, specifically the relationship between angular speed and tangential speed. The key formula presented is V = ωr, where V represents linear speed, ω is the angular speed in radians per second, and r is the radius from the axis of rotation. It is explained that in one second, a rotating object covers a distance equal to the product of its angular speed and radius. The conversation clarifies that understanding this relationship is crucial for demonstrating how rotational motion translates to linear motion. Overall, the formula V = ωr effectively illustrates this conversion.
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I can define both terms Linear Speed, Rotational speed,

but I need to find the formula difference so I can show how

rotational speed is changed to linear Speed.

I can not find the formula for either.
 
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I assume you are talking about how to find the tangential speed (V) of something that is rotating about a point at some angular speed (ω, measured in radians/sec). The relationship is V=ωr, where r is the distance to the axis of rotation.
 
If the angular speed is ω, measured in radians per second, that means that in 1 second, the "wheel" will turn through ω radians. On a "wheel" of radius r, one radian angle cuts an arc of length r*1= r on the circumference of the wheel (remember that the full circle is 2π radians and the entire circumference is 2πr).
That is, in one second there is a revolution of ω radians which carries a point on the circumference a distance rω.
Angular speed ω corresponds to a linear speed of v= rω, just as Doc Al said.
 
Thanks to all.
I now understand
v=w*r
v= linear speed
w= Rotational Speed
r=radius
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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