What is the Formula for Determining Height in Newton's Law of Gravitation?

Click For Summary

Homework Help Overview

The problem involves determining the height at which a person's weight is reduced to one-fifth of their weight at the Earth's surface, using Newton's law of gravitation. The radius of the Earth is provided as 6400 km.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between gravitational force and distance from the Earth's surface, with some suggesting the use of ratios and equations to express the problem. There are attempts to formulate equations based on gravitational force and acceleration due to gravity.

Discussion Status

The discussion is active, with participants exploring different interpretations of the problem and attempting to derive equations. Some guidance has been offered regarding the formulation of the problem, but there is no explicit consensus on the approach to take.

Contextual Notes

Participants are navigating the constraints of the problem, including the need to express gravitational force in terms of height and the implications of distance on weight. There is uncertainty regarding the relevance of centripetal acceleration in this context.

science_rules
Messages
157
Reaction score
2

Homework Statement


Starting with Newton's law of gravitation, determine the height h one person has to go from the surface of Earth in order for the person's weight to be reduced to 1/5 of their weight at the surface of the Earth. The only information you are given is that the radius of the Earth is 6400 km.


Homework Equations


GM_e/r^2, r = R_e + h


The Attempt at a Solution


i know that 4 times R_e at the center(of earth) is equal to 3 times R_e at the surface. I am not sure how to find the height using Newton's Law.
 
Physics news on Phys.org
Well, what are you asked to actually compare?

Try to formulate an equation that incorporates this, what you have called equations are not that at all.
 
hi science_rules

So the problem effectively says the gravitational force at the surface (r1=Re) is 5 times the force at (r2=Re+h). Equivalently you can consider the acceleration due to gravity (why?)

So try writing this out as an equation, then solving for h
 
a person's weight is dependent on how far out you are from the surface, and the weight is reduced as the distance is increased. should it be some kind of ratio problem? could it be: GM_em/ r^2 = 1/5 (GM_em)/R_e^2

r^2 = 5R_e^2 where r = (squrrt5)R_e = 2.23R_e = 14272 km
 
a_c = v^2 / r but what does that have to do with the height? you don't know the velocity, but you don't need the velocity to get the height.
 
post #4 looked good, then h = r - Re

i'm not too sure about post #5, i don't think you need to look at centripetal acceleration in this problem
 

Similar threads

Replies
3
Views
2K
  • · Replies 29 ·
Replies
29
Views
4K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
3K
Replies
2
Views
3K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 5 ·
Replies
5
Views
7K
  • · Replies 12 ·
Replies
12
Views
3K