What is the Frénet-frame of a streamline at a given point?

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    Calc iii
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Homework Help Overview

The problem involves finding the Frénet-frame of a streamline represented by the vector function \textbf{r}(t) = \left(\frac{1}{2} \cosh t, e^t, \frac{1}{2} \cosh t\right) at the specific point (1,1,1). The discussion centers around the definitions and calculations of the tangent vector \textbf{T}(t), the binormal vector \textbf{B}(t), and the normal vector \textbf{N}(t).

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to clarify how to incorporate the point (1,1,1) into the calculations for \textbf{T}, \textbf{B}, and \textbf{N}. Some participants confirm the approach and provide calculations for \textbf{T}(t).

Discussion Status

The discussion is ongoing, with participants sharing their calculations and confirming the steps taken so far. There is no explicit consensus, but guidance has been provided regarding the calculation of the tangent vector.

Contextual Notes

Participants are considering how to evaluate the vectors at the given point and are discussing the implications of that point in the context of the Frénet-frame.

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Homework Statement


Find the Frénet-frame of the streamline [itex]\textbf{r}(t) = \left(\frac{1}{2} \cosh t, e^t, \frac{1}{2} \cosh t\right)[/itex] at the point [itex](1,1,1)[/itex]

Homework Equations



[itex]\textbf{T}(t) = \frac{\textbf{r}'(t)}{||\textbf{r}'||}[/itex]
[itex]\textbf{B}(t) = \frac{\textbf{r}'(t) \times \textbf{r}''(t)}{||\textbf{r}'(t) \times \textbf{r}''(t)||}[/itex]
[itex]\textbf{N}(t) = \textbf{B}(t) \times \textbf{T}(t)[/itex]

The Attempt at a Solution


This is pretty straightforward. The only thing that is confusing me is what to do with [itex](1,1,1)[/itex]. Do I find T,B,N and plug [itex](1,1,1)[/itex] into that?

Thanks
 
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Pretty much
 
To be on the safe side here is how I calculated T.

[itex]\textbf{r}'(t) = \left(\frac{1}{2} \sinh t, e^t, \frac{1}{2} \sinh t\right)[/itex]

[itex]||\textbf{r}'(t)|| = \displaystyle \sqrt{(\frac{1}{2} \sinh t)^2 + (e^t)^2 + (\frac{1}{2} \sinh t)^2} = \sqrt{\frac{1}{2} \sinh ^2 t + e^{2t}}[/itex]

So

T(t) = [itex]\displaystyle \frac{\left(\frac{1}{2} \sinh t, e^t, \frac{1}{2} \sinh t\right)}{\sqrt{\frac{1}{2} \sinh ^2 t + e^{2t}}}[/itex]

and

T(1,1,1) = [itex]\displaystyle \frac{\left(\frac{1}{2} \sinh 1, e, \frac{1}{2} \sinh 1\right)}{\sqrt{\frac{1}{2} \sinh ^2 1 + e^{2}}}[/itex]
 
Looks fine to me, so far.
 

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