What is the frequency of note y if it is two sext higher than note x?

[songoku]

Homework Statement

Given that note x has frequency 300 Hz. Find the frequency of note y if it is two sext higher than x.

Homework Equations

sext interval --> x : y = 24 : 40

The Attempt at a Solution

I can find the value of y if the interval is sext.

x : y = 24 : 40
300 : y = 24 : 40
y = 500 Hz

two sext higher means that y = 2 x 500 = 1000 Hz?

Thanks

 

[gneill]

Why not apply the relationship twice?

500/y = 24/40

y = 833.33

 

[songoku]

Why not apply the relationship twice?

500/y = 24/40

y = 833.33

Very good point. Why don't that idea even cross my mind...

Thanks for the help gneill