What is the frequency of note y if it is two sext higher than note x?

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SUMMARY

The frequency of note y, which is two sext higher than note x with a frequency of 300 Hz, is calculated using the sext interval ratio of 24:40. Initially, note y is determined to be 500 Hz based on the ratio. However, applying the relationship twice leads to a more accurate frequency of 833.33 Hz for note y. This discussion highlights the importance of correctly applying musical interval relationships in frequency calculations.

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  • Familiarity with ratio and proportion concepts.
  • Ability to apply mathematical relationships multiple times for accuracy.
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Homework Statement


Given that note x has frequency 300 Hz. Find the frequency of note y if it is two sext higher than x.


Homework Equations


sext interval --> x : y = 24 : 40


The Attempt at a Solution


I can find the value of y if the interval is sext.

x : y = 24 : 40
300 : y = 24 : 40
y = 500 Hz

two sext higher means that y = 2 x 500 = 1000 Hz?

Thanks
 
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Why not apply the relationship twice?

500/y = 24/40

y = 833.33
 
gneill said:
Why not apply the relationship twice?

500/y = 24/40

y = 833.33

Very good point. Why don't that idea even cross my mind...

Thanks for the help gneill :smile:
 

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