What is the Frictional Force Acting on a Toy Being Dragged by a Child?

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Homework Help Overview

The discussion revolves around a physics problem involving a toy being dragged along a rough floor by a child. The problem consists of multiple parts, including determining the frictional force when a constant horizontal force is applied, calculating acceleration when the force is increased, and finding the mass of the toy.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the use of the frictional force equation and question whether all necessary variables are available for calculations. They discuss the implications of constant velocity and zero acceleration in relation to net force.

Discussion Status

Participants are actively engaging with the problem, offering guidance on how to approach the calculations based on the information provided. There is a focus on using results to derive necessary values rather than solely relying on equations.

Contextual Notes

Some participants note the lack of certain variables, such as mass and the coefficient of friction, which may affect the ability to apply certain equations directly. The discussion also reflects a learning environment where participants are encouraged to clarify their understanding of the concepts involved.

inzektor95
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Homework Statement



a toy is dragged along a rough floor by a child

(a) when the child applies a force of 0.50N horizontally the velocity is contant at 1.0 m/s. What is the force of friction on the toy?

(b)when the child pulls harder so that the applied force is 1.00N the velocity of the toy increases uniformly to 2.0 m/s in 5.0 seconds. Calculate the acceleration of the block.

(c) find the mass of the toy

Homework Equations



(a) Do I have to use the frictional force equation to find the answer? (Ffric = μ* F norm)

(b) should I use the net force equation? Fnet=M*A

The Attempt at a Solution



(A)I was considering using the frictional force equation to solve the problem but I don´t have all the variables

(B) Velocity v Time graph perhaps?

thanks for the help (I´m a noob in physics)
 
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welcome to pf!

hi inzektor95! welcome to pf! :smile:
inzektor95 said:
a toy is dragged along a rough floor by a child

(a) when the child applies a force of 0.50N horizontally the velocity is contant at 1.0 m/s. What is the force of friction on the toy?

(b)when the child pulls harder so that the applied force is 1.00N the velocity of the toy increases uniformly to 2.0 m/s in 5.0 seconds. Calculate the acceleration of the block.

(c) find the mass of the toy

(a) Do I have to use the frictional force equation to find the answer? (Ffric = μ* F norm)

nope!

you can find the friction force either from the cause or from the result

from the cause, you would need to know the mass and the coefficient of friction … you don't, so that's out!

from the result, you know the acceleration is zero, so you should be able to find the force of friction from the information given :wink:

for part (b), again you could find the acceleration either from the cause or from the result …

ues the result … you know the initial velocity the final velocity and the time, so use one of the standard constant acceleration equations :wink:
 
Thanks for the quick reply :)

For A

how can i find the force of friction using the information given? do i have to use a specific equation?

acceleration = 0
velocity = 1.0 m/s
force = 0.50N

For part B

Vi (initial)= 1.0 m/s
Vf (final)= 2.0 m/s
T = 5.0 s
A = ?

so in other words, I should use this equation?
Vf = Vi + at

thank you very much tiny-tim! :D
 
hi inzektor95! :smile:
inzektor95 said:
For A

how can i find the force of friction using the information given? do i have to use a specific equation?

acceleration = 0
velocity = 1.0 m/s
force = 0.50N

if the acceleration is 0, what is the net force? :wink:
For part B

Vi (initial)= 1.0 m/s
Vf (final)= 2.0 m/s
T = 5.0 s
A = ?

so in other words, I should use this equation?
Vf = Vi + at

yup! :biggrin:
 
thank you very much tiny tim:smile:
 

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