What Is the Fringe Width in Young's Double Slit Experiment with Red Light?

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SUMMARY

The fringe width in Young's Double Slit Experiment is directly proportional to the wavelength of light used. In this discussion, the fringe width for green light was measured at 0.20 mm with a wavelength of 5.2 x 10-7 m. When red light, with a wavelength of 6.5 x 10-7 m, replaces green light, the fringe width increases proportionally. The calculated fringe width for red light is 0.25 mm, derived from the ratio of the wavelengths.

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Homework Statement


In a Youngs dbl. slit experiment using green light the fringe width was observed to be 0.20mm.if red light replaces green light,what will be the fringe width?


Homework Equations


hmm lambda=ay/d but (no info is given on rest)=/
wavelengths:green=5.2x10^-7m ,red=6.5x10^-7m

The Attempt at a Solution


well i don't know if its correct but i tried to solve it.by dividing the wavelength of of red over greens and i got 1.25m which i multiplied to (2x10^-4) <---- which is the fringe width of green .=/ i totally made it up .sos here =)
 
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Hey ibysaiyan,

Your method is right but now I want you to explain why it is. What do we know about d, n and L in the equation:

[tex]n \lambda \ = \ \frac{xd}{L}[/tex]

in relation to this question?

The Bob

http://en.wikipedia.org/wiki/Double-slit_experiment
 

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