What Is the G-Loading on an Aircraft During a Steady Pull-Up Maneuver?

[marklar13]

Homework Statement

Consider an aircraft flying with speed 300 ft/s in a steady pull-up maneuver with pitch rate q = 0.1 rad/sec.

What is the g-loading experienced by the pilot of the aircraft just as the maneuver begins (i.e. when the aircraft is still level)?

The attempt at a solution

So the first step is to find the radius of curvature of the maneuver from:

R=V/q=(300 ft/s)/(0.1 rad/s) --> R=3000 ft

Then, I believe you find the acceleration of the aircraft from:

G=(V^2)/R=(300^2)/3000 --> G=30 ft/s^2

So, since 1 g = 32.174 ft/s^2

The g force (without Earth's g) is 30/32.174=.932 g

Adding that to the 1 g due to Earth the answer would be 1.932 g?

Is that correct?

 

[tiny-tim]

hi marklar13!

Then, I believe you find the acceleration of the aircraft from:

G=(V^2)/R=(300^2)/3000 --> G=30 ft/s^2

So, since 1 g = 32.174 ft/s^2

The g force (without Earth's g) is 30/32.174=.932 g

yes that's fine

(though you could save time by using ωv for the centripetal acceleration … ωv = ω²r = v²/r )