What is the gear ratio and horsepower required for an ECAP machine gearbox?

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Discussion Overview

The discussion revolves around determining the gear ratio and horsepower required for a gearbox in an ECAP (Equal Channel Angular Pressing) machine, focusing on the technical specifications needed for the design and performance of the machine.

Discussion Character

  • Technical explanation, Homework-related, Mathematical reasoning

Main Points Raised

  • One participant states the requirement for the gearbox to provide an output torque of 2,000,000 lb-ft at an output shaft rpm of 0.42, with motor speeds of 1,800 rpm and 1,200 rpm.
  • Another participant suggests that the horsepower can be calculated using the formula HP = torque * rpm / 5252, and mentions finding the horsepower to be 160.
  • A different participant questions the calculation of the gear ratio, proposing that it might be 1.5 based on the motor speeds.
  • One participant recommends converting output speed to radians per second and manipulating units to find horsepower, while also considering gearbox efficiency.
  • Another participant advises checking gearmotor manufacturer websites for downloadable catalogs and online selection tools that could assist in determining the correct gear ratio and horsepower.

Areas of Agreement / Disagreement

There is no consensus on the gear ratio calculation, as participants express uncertainty and propose different methods. The discussion remains unresolved regarding the exact gear ratio and horsepower needed.

Contextual Notes

Participants express varying levels of confidence in their calculations and approaches, indicating potential limitations in their understanding of the required conversions and efficiency considerations.

yosty02
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Our lab is looking at designing a new ECAP machine (Equal Channel Angular Pressing). It needs to be driven by an electric motor attached to a gearbox. From their modeling and data collected from their existing ECAP machine they are requesting the output shaft on the gearbox to have a 2,000,000 lb-ft of torque, the output shaft rpm is .42, using a 1,800 rpm and 1,200 motor speed. Find the gear ratio required and the horsepower required and give actual gearbox output torque with the motor hp selected to check safety factor, use 85% efficiency for the gearbox.
 
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I found the HP to be 160. By HP = torque*rpm/5252.
I'm not quite sure about the gear ratio, is it 1800/1200 = 1.5?
I'm an intern and my boss said something about the gear ratio being high, so I'm just thrown off a bit.
 
I'd convert the output speed to radians per second. Them I'd multiply that by the output torque, being careful to properly manipulate the units into HP. Them I'd apply the gearbox efficiency backwards to the motor.
 
Go to any gearmotor manufacturer website (Dodge, Emerson, Falk, Nord, SEW-Eurodrive) and check out their downloadable catalogs. Usually those catalogs have engineering sections with all the necessary & correct calculations. Many times those sites will have online selection tools that make it simple to select the correct gear ratio, horsepower, style, and size.
 

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