What is the general solution for b_r here ?

Click For Summary
SUMMARY

The discussion centers on the mathematical identity involving the series \(\sum^{\infty}_{r=0}\frac{b_r}{r+n+1}\) and its equivalence to \({[\sum^{\infty}_{r=0}\frac{b_r}{r+2}]}^{n}\). The constant \(T\) plays a crucial role in the formulation, leading to the integral representation \(\int_{T}t^{n}f(t)dt={(\int_{T}tf(t)dt)}^{n}\). The focus is on determining the function \(f(t)\) that satisfies this identity.

PREREQUISITES
  • Understanding of infinite series and convergence
  • Familiarity with integral calculus and properties of integrals
  • Knowledge of mathematical notation and functions
  • Basic understanding of constants in mathematical expressions
NEXT STEPS
  • Research the properties of infinite series and their convergence criteria
  • Study integral calculus, specifically techniques for solving integrals involving functions
  • Explore the concept of functional equations and their applications
  • Investigate the role of constants in mathematical identities and their implications
USEFUL FOR

Mathematicians, students studying advanced calculus, and anyone interested in the analysis of infinite series and integrals.

mmzaj
Messages
107
Reaction score
0
[tex]\sum^{\infty}_{r=0}\frac{Tb_r}{r+n+1}[/tex] = [tex]{[\sum^{\infty}_{r=0}\frac{b_r}{r+1}]}^{n}[/tex]

T is a constant .

latex needs to be improved deeply :)
 
Physics news on Phys.org
sorry , this is the correct formula .


[tex]\sum^{\infty}_{r=0}\frac{b_r}{r+n+1}[/tex]=[tex]{[\sum^{\infty}_{r=0}\frac{b_r}{r+2}]}^{n}[/tex]
 
the above is somehow equivalent to :

[tex]\int_{T}t^{n}f(t)dt[/tex]=[tex]{(\int_{T}tf(t)dt)}^{n}[/tex]

now f(t) is to be found in general .
 
Last edited:

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K