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What is the general solution for b_r here ?

  1. Apr 25, 2008 #1
    [tex]\sum^{\infty}_{r=0}\frac{Tb_r}{r+n+1}[/tex] = [tex]{[\sum^{\infty}_{r=0}\frac{b_r}{r+1}]}^{n}[/tex]

    T is a constant .

    latex needs to be improved deeply :)
     
  2. jcsd
  3. Apr 26, 2008 #2
    sorry , this is the correct formula .


    [tex]\sum^{\infty}_{r=0}\frac{b_r}{r+n+1}[/tex]=[tex]{[\sum^{\infty}_{r=0}\frac{b_r}{r+2}]}^{n}[/tex]
     
  4. Apr 26, 2008 #3
    the above is somehow equivalent to :

    [tex]\int_{T}t^{n}f(t)dt[/tex]=[tex]{(\int_{T}tf(t)dt)}^{n}[/tex]

    now f(t) is to be found in general .
     
    Last edited: Apr 26, 2008
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