What is the general solution for b_r here ?

  • Thread starter mmzaj
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[tex]\sum^{\infty}_{r=0}\frac{Tb_r}{r+n+1}[/tex] = [tex]{[\sum^{\infty}_{r=0}\frac{b_r}{r+1}]}^{n}[/tex]

T is a constant .

latex needs to be improved deeply :)
 

Answers and Replies

107
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sorry , this is the correct formula .


[tex]\sum^{\infty}_{r=0}\frac{b_r}{r+n+1}[/tex]=[tex]{[\sum^{\infty}_{r=0}\frac{b_r}{r+2}]}^{n}[/tex]
 
107
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the above is somehow equivalent to :

[tex]\int_{T}t^{n}f(t)dt[/tex]=[tex]{(\int_{T}tf(t)dt)}^{n}[/tex]

now f(t) is to be found in general .
 
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