# What is the general solution for b_r here ?

1. Apr 25, 2008

### mmzaj

$$\sum^{\infty}_{r=0}\frac{Tb_r}{r+n+1}$$ = $${[\sum^{\infty}_{r=0}\frac{b_r}{r+1}]}^{n}$$

T is a constant .

latex needs to be improved deeply :)

2. Apr 26, 2008

### mmzaj

sorry , this is the correct formula .

$$\sum^{\infty}_{r=0}\frac{b_r}{r+n+1}$$=$${[\sum^{\infty}_{r=0}\frac{b_r}{r+2}]}^{n}$$

3. Apr 26, 2008

### mmzaj

the above is somehow equivalent to :

$$\int_{T}t^{n}f(t)dt$$=$${(\int_{T}tf(t)dt)}^{n}$$

now f(t) is to be found in general .

Last edited: Apr 26, 2008