What is the Gravitational Force Between the Moon and a 50-kg Student?

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Homework Help Overview

The problem involves calculating the gravitational force between the Moon and a 50-kg student, using the gravitational force formula. The context includes a discussion about the unusual behaviors attributed to the full moon and the specifics of the calculation, including the distance from the Earth and the mass of the Moon.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the gravitational force formula and the calculations involved. There are attempts to verify the correctness of the numerical values used in the calculations, particularly focusing on the order of magnitude in the numerator and denominator.

Discussion Status

Multiple participants have pointed out potential errors in the calculations, suggesting that the original poster should re-evaluate their numerical inputs. There is an ongoing exploration of the calculations, with some participants providing feedback on the results obtained.

Contextual Notes

Participants note discrepancies in the calculations and the importance of correctly squaring the distance in the denominator. There is an acknowledgment of previous mistakes in the calculations that may have led to incorrect answers.

STrain
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Homework Statement



It is said that people often behave in unusual ways during a full moon. a) Calculate the gravitational force that the moon would exert on a 50.0-kg student in your physic's class. The moon is 3.84 x 108m from the Earth and has a mass of 7.35 x 1022kg. b) Does the moon attract the student with a force that is greater than, less than, or the same as, the force with which the student attracts the moon?

Homework Equations



F = G times m1 times m2 divided by d squared

or

F = G * m1 *m2 / d^2

The Attempt at a Solution

A) The force of attraction or the gravitational force between two objects is the product of the two masses divided by the distance between the two objects squared, all multiplied by the gravitational constant.

F = the force of attraction between two masses
G = gravitational constant
m1, m2 = the two masses
d = the distance between the two masses

F = G times m1 times m2 divided by d squared

or

F = G * m1 *m2 / d^2

so F = (6.67*10^-11)*(50)*(7.35*10^22) / (3.84*10^8)^2 then

F = 0.0016623433

B) They both attract each other the same amount
 
Last edited:
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The answer to (a) is incorrect. Try plugging in the numbers again.
 
kuruman said:
The answer to (a) is incorrect. Try plugging in the numbers again.

Is A correct now? when i originally posted i put in 9. something by accident is the 6.38 correct?
 
Last edited:
No, 6.38 (I assume Newtons) is not correct. Like I said, redo the calculation. Look at your expression, the numerator is on the order of 1014 and the denominator is on the order of 1016. You can't get an answer n the order of 1.
 
kuruman said:
No, 6.38 (I assume Newtons) is not correct. Like I said, redo the calculation. Look at your expression, the numerator is on the order of 1014 and the denominator is on the order of 1016. You can't get an answer n the order of 1.

Thanks for the help, I realize that when squaring the denominator i was squaring just the ^8 instead of the whole problem and now that i fixed that I got

F = 0.0016623433
 
That's about right.
 

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