What is the height at which the ball starts to move on a ramp?

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The ball starts to move from a height of 1.45 meters above the ground when sliding down a frictionless track. The calculation is based on the conservation of energy principle, represented by the equation mgh = mgh2 + 1/2mv^2. Given the height from the bottom of the ramp to the ground is 1.25 meters, the total height (h) is determined to be 1.45 meters, accounting for the additional distance the ball travels horizontally.

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Homework Statement


A ball of mass 522 g starts at rest and slides down a frictionless track. It leaves the track horizontally, striking the ground.
a. at what height above the ground does the ball start to move?

Homework Equations


I have:
mgh=mgh_2+1/2mv^2
which simplifies to:
h=h_2+1/2mv^2

The Attempt at a Solution


I got:
.2+1.25=1.45

I think that 1.45 is right, but I'm a little confused on how I got to that point.:confused: Any help is most appreciated. Thanks.
 
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uhhhh,
I think the problem probably gave a little more information then that.
 
Oh, so sorry, it did. There was the variable h that was the height of top of ramp to ground. then there was height from bottom of ramp to ground which was 1.25 meters and then distance the ball fell from ramp in x direction which was 1 meter.
 

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