What is the Height of Each Fluid in the U-Tube Arm with Oil-to-Water Ratio of 4?

Click For Summary
SUMMARY

The discussion focuses on calculating the height of fluids in a U-tube containing water and light oil with a density of 790 kg/m³, where the oil-to-water height ratio is 4. Given that one arm of the U-tube has a water height of 70 cm, the equilibrium pressure equations are established as P = ρ_water * g * H and P = ρ_water * g * H1 + ρ_oil * g * 4H1. By equating these pressures and canceling gravity (g), the height of the oil (H1) can be determined using known values.

PREREQUISITES
  • Understanding of fluid mechanics principles, specifically hydrostatic pressure.
  • Knowledge of density calculations for fluids.
  • Familiarity with equilibrium conditions in fluid systems.
  • Basic algebra for solving equations.
NEXT STEPS
  • Study hydrostatic pressure calculations in fluid mechanics.
  • Learn about the properties of different fluids, focusing on density and buoyancy.
  • Explore equilibrium conditions in U-tube manometers.
  • Investigate applications of fluid dynamics in engineering contexts.
USEFUL FOR

Students and professionals in engineering, particularly those studying fluid mechanics, as well as anyone involved in practical applications of hydrostatic pressure and fluid equilibrium analysis.

wub1098
Messages
3
Reaction score
0
Consider a U-tube whose arms are open to the atmosphere. Now water is poured into the U-tube from one arm, and light oil (p=790 kg/m^3) from the other. One arm contains 70 cm high water, while the other arm contains both fluids with an oil-to-water height ratio fo 4. Determine the height of each fluid in that arm.


any help an explanation would be greatly appreciated
 
Engineering news on Phys.org
Ok simple, we know that the pressure exerted by a fluid is explained by the following relation: P= rho * g * height of water. g is the gravity. now on the water side we have P = Rho of water*g*H on the other side we have
P= Rho water*g*H1 + Rho Oil*g*4H1 (since height of oil is 4 times that of water). since we are in equilibrium then the pressures will be equal. P1=P2. g cancels from both equations, and the rest are known values leaving us with H1 to figure out.Easy ?
 
btw this is not even close to thermodynamics !
 
Please re read the forum's guidlines for the posting of homeowork questions as well as providing answers.
 

Similar threads

Replies
7
Views
5K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 18 ·
Replies
18
Views
7K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
7K
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K