What is the Height of Each Fluid in the U-Tube Arm with Oil-to-Water Ratio of 4?

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Discussion Overview

The discussion centers around determining the heights of fluids in a U-tube containing water and oil, specifically with an oil-to-water height ratio of 4. The context involves fluid statics and pressure equilibrium in a U-tube setup.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant describes the setup of the U-tube and the initial conditions, including the height of water and the oil-to-water ratio.
  • Another participant proposes a mathematical approach to find the height of the oil and water in equilibrium, using the pressure equations for both sides of the U-tube.
  • A third participant comments that the problem does not pertain to thermodynamics, suggesting a focus on fluid mechanics instead.
  • A fourth participant reminds others to adhere to forum guidelines regarding homework questions and answers.

Areas of Agreement / Disagreement

There is no consensus on the approach to the problem, as participants express differing views on the relevance of the topic and the appropriateness of the question format.

Contextual Notes

Participants have not fully resolved the mathematical steps needed to determine the heights of the fluids, and there are indications of differing interpretations of the problem's classification.

wub1098
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Consider a U-tube whose arms are open to the atmosphere. Now water is poured into the U-tube from one arm, and light oil (p=790 kg/m^3) from the other. One arm contains 70 cm high water, while the other arm contains both fluids with an oil-to-water height ratio fo 4. Determine the height of each fluid in that arm.


any help an explanation would be greatly appreciated
 
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Ok simple, we know that the pressure exerted by a fluid is explained by the following relation: P= rho * g * height of water. g is the gravity. now on the water side we have P = Rho of water*g*H on the other side we have
P= Rho water*g*H1 + Rho Oil*g*4H1 (since height of oil is 4 times that of water). since we are in equilibrium then the pressures will be equal. P1=P2. g cancels from both equations, and the rest are known values leaving us with H1 to figure out.Easy ?
 
btw this is not even close to thermodynamics !
 
Please re read the forum's guidlines for the posting of homeowork questions as well as providing answers.
 

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