What is the Hill Sphere and how is its formula derived?

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SUMMARY

The Hill sphere defines the region around a celestial body where it exerts dominant gravitational influence. The formula for the radius of the Hill sphere, given a smaller body of mass m orbiting a larger body of mass M with a semi-major axis a and eccentricity e, is expressed as r ≈ a(1-e)√[3]{m/3M}. This formula is distinct from the Laplace Sphere, which is often confused with it. The correct derivation can be found in Astrodynamics lecture notes and is crucial for understanding gravitational interactions in celestial mechanics.

PREREQUISITES
  • Understanding of celestial mechanics
  • Familiarity with gravitational forces and orbits
  • Knowledge of semi-major axis and eccentricity
  • Basic grasp of mathematical derivations in physics
NEXT STEPS
  • Study the derivation of the Hill sphere formula in Astrodynamics lecture notes
  • Explore the differences between the Hill sphere and Laplace sphere
  • Learn about Lagrange Points L1 and L2 and their significance
  • Investigate the applications of the Hill sphere in satellite dynamics
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Astronomers, astrophysicists, and students of celestial mechanics who are interested in gravitational influences and orbital dynamics.

Ryan H
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The Hill sphere of a celestial object is the area in which it is the dominating force in the area.

I was wondering how the formula was determined.

If the mass of the smaller body is m, and it orbits a heavier body of mass M with a semi-major axis a and an eccentricity of e, then the radius r of the Hill sphere for the smaller body is, approximately:

Equation: r \approx a(1-e)\sqrt[3]{m/3M}

I believe I understand how to determine eccentricity and the semi-major axis, I'm just searching for how the whole thing comes together.

http://en.wikipedia.org/wiki/Hill_sphere"

The derivation on the wikipedia article didn't help much.
 
Last edited by a moderator:
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Ryan H said:
The Hill sphere of a celestial object is the area in which it is the dominating force in the area.

I was wondering how the formula was determined.

If the mass of the smaller body is m, and it orbits a heavier body of mass M with a semi-major axis a and an eccentricity of e, then the radius r of the Hill sphere for the smaller body is, approximately:

Equation: r \approx a(1-e)\sqrt[3]{m/3M}

I believe I understand how to determine eccentricity and the semi-major axis, I'm just searching for how the whole thing comes together.

http://en.wikipedia.org/wiki/Hill_sphere"

The derivation on the wikipedia article didn't help much.

The reason why it didn't help is that it's wrong. The derivation is for the Laplace Sphere, which is a related concept but distinct mathematically...

as discussed here on Physforums before

...there's Astrodynamics lecture notes available online covering it, but I'll have to track them down.
 
Last edited by a moderator:
qraal said:
The reason why it didn't help is that it's wrong. The derivation is for the Laplace Sphere, which is a related concept but distinct mathematically...

as discussed here on Physforums before

...there's Astrodynamics lecture notes available online covering it, but I'll have to track them down.

I tracked down my old copies of the University of Wisconsin EMA 550 lectures and the Wikipedia entries. The equation for the Sphere of Influence aka the Hill sphere has been confused with the Lagrange Points L1 & L2. They're similar concepts in some features, so it's an understandable confusion. So it goes like so...

R_{H} = a \left(\frac{M_{\mathrm{minor}}}{M_{\mathrm{major}}}\right)^{2/5}

...and the L1 & L2 points are found (+/-) in line with the the minor body's semimajor axis around the major body via...

R_L = a \left(\frac{M_{\mathrm{minor}}}{3M_{\mathrm{major}}}\right)^{1/3}
 

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