What is the hybridization of C in R - N=C=O

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Discussion Overview

The discussion centers on the hybridization of carbon in the isocyanate group (R - N=C=O), exploring the theoretical basis for determining hybridization in this context.

Discussion Character

  • Technical explanation, Debate/contested

Main Points Raised

  • One participant asserts that the carbon is sp-hybridized.
  • Another participant questions the basis of the sp-hybridization claim, asking for supporting reasoning.
  • A different participant states that carbons bound to two atoms with no lone pairs are sp-hybridized, suggesting a general rule.
  • One participant draws a comparison to carbon dioxide (O=C=O) to illustrate the concept, providing a link to a visual model.
  • Another participant explains that the presence of two double bonds leads to sp hybridization, noting the role of unhybridized p-orbitals in forming pi bonds.

Areas of Agreement / Disagreement

Participants express differing views on the hybridization of carbon, with no consensus reached on the reasoning behind the claims made.

Contextual Notes

Some assumptions about hybridization rules and the specific structure of the isocyanate group may not be fully articulated, leading to potential gaps in understanding.

WACG
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R - N=C=O is the isocyanate group.

I have been trying to use a molsym program and it requires that value as input? The starting value is important. Thanks for any info.
 
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The carbon is sp-hybridized.
 
Well, thanks for the response but I cannot decide whether you are simply guessing or not. Do you have any reason that supports your response? Thanks
 
Carbons bound to two atoms and containing no lone pairs are sp hybridized.
 
Pi bonds are made by sharing the unhybridized p-orbitals. Carbon in this case has two double bonds, containing one pi bond each, while also having two sigma bonds - one with Nitrogen and the other with Oxygen. Therefore, the hybridization is sp with 2 unhybridized p orbitals.
 

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