What is the identity of element M in the reaction with fluorine?

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SUMMARY

The identity of element M in the reaction with fluorine is calcium, determined through stoichiometric calculations involving the formation of MF2. A sample of 0.6 moles of metal M reacts with excess fluorine to produce 46.8 grams of MF2. The calculation reveals that 0.6 moles of MF2 contains 1.2 moles of fluorine, leading to the conclusion that the molar mass of element M is 40 g/mol, which corresponds to calcium.

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Homework Statement


a sample of 0.6 moles of a metal M reacts completely with excess of flourine to form 46.8 gms of MF2.
a)how many moles of F are present in the sample of MF2 that forms?
b)which element is represented by the symbol M?


Homework Equations


NO. OF MOLES=given mass/molar mass


The Attempt at a Solution


molesof element M:moles of compound formed MF2
1 : 1
0.6 : 0.6
1 mole of MF2 contains 2 moles of F
0.6 MOLES WOULD CONTAIN=0.6*2=1.2

now i dnt no how can i find which element it is
 
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Think how you can calculate its molar mass from the information given.

--
methods
 
i tried my best i m nt getting which formula to use
 
A little more: how much MF2 do you have at the end of your reaction?
 
Tedjn said:
A little more: how much MF2 do you have at the end of your reaction?
total MF2=46.8GMS
atomic mass of flourine=19 g/mol
mass=moles*atomic mass
=0.6*19
= 22.8gms
hence
mass of element M=46.8-22.8
=24gms
molar mass of element M=mass of M/moles of M
=24GMS/0.6
=40 g/mol
atomic mass of element M=40g/mol
this is atomic mass of calcium
 
so the element is calcium

thnx a lot for ur help
 
Wasn't that hard :wink
 

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