What is the importance of the solution in an electrochemical cell?

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SUMMARY

The electrolytic solution in an electrochemical cell is crucial for facilitating redox reactions, as demonstrated by the Zn/ZnSO4 and Cu/CuSO4 systems. The electrochemical series indicates that zinc (Zn) will reduce copper ions (Cu2+) in solution, leading to the deposition of copper on the electrode. An inert electrode, such as silver (Ag), can still participate in the reaction as long as the necessary ions are present in the solution. In scenarios involving Ag/AgNO3 and Cu/Zn(NO3)2, zinc ions act as spectators, allowing copper to displace silver in the reaction.

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stfz
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I'm wondering about the importance of the electrolytic solution in an electrochemical cell.
For example, we have Zn/ZnSO4 and Cu/CuSO4.
According to the electrochemical series, Zn will reduce Cu, and we will have a reaction.
Zn(s) -> Zn2+(aq), Cu2+(aq) -> Cu(s).
So there MUST be Cu2+ in the solution. But what about the electrode? If I had an Ag electrode in a copper solution, would the reaction proceed? (I am told it will not... but why?) The same net reaction would take place - Zn reducing Cu in solution, causing Cu to plate onto Ag. The only difference is that the electrode carrying electrons is now Ag.
Similarly, if I had a Ag/AgNO3 solution and a Cu/Zn(NO3)2 solution, would Cu displace Ag in solution still? I mean, Cu oxidize to Cu2+ and enter solution even if there is Zn(NO3)2?
Somewhat confused :P
Help would be appreciated :)
 
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stfz said:
If I had an Ag electrode in a copper solution, would the reaction proceed?

Yes. Electrode can be inert in this case - besides, once few first copper atoms get reduced, you are back at a square one, copper electrode and copper in the solution.

stfz said:
Similarly, if I had a Ag/AgNO3 solution and a Cu/Zn(NO3)2 solution, would Cu displace Ag in solution still?

Yes, Zn2+ would be just a spectator.

2Ag+ + Cu -> 2Ag + Cu2+
 

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